我试图从资源文件动态获取XML数组但是我不断收到异常编号错误。
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
View rootView = inflater.inflate(R.layout.fragment_class, container, false);
TextView classTitle = (TextView) rootView.findViewById(R.id.class_title);
classTitle.setText(getString(R.string.section_format, getArguments().getInt(ARG_SECTION_NUMBER)));
//FETCH THE XML ARRAY
String[] classAvgArray = getResources().getStringArray(R.array.classAvg);
//INDEX OF THE ARRAY
int key = getArguments().getInt(ARG_SECTION_NUMBER);
//DISPLAY THE AVG AMOUNT
TextView classTextAverage = (TextView) rootView.findViewById(R.id.classAvgAmount);
classTextAverage.setText("Avg: "+classAvgArray[key]);
//FETCH THE XML ARRAY FOR ITEMS
String ID = "c"+key;
int resID = getResources().getIdentifier(ID, "R.array.c"+key, "za.co.infomycito.mycitoapp");
String[] classactivities = getResources().getStringArray(resID);
答案 0 :(得分:1)
我认为你应该做这样的事情
int resID = getResources().getIdentifier("c"+key, "array", getPackageName());
如果您想获取R.array.c<key>
的资源ID。