Question

我的代码是：

for datum in data :
        sick.append(datum[2])

，结果是

sick=['J02', 'J02', 'J20', 'J20', 'J20', 'J20', 'J20', 'A08', 'J45','A08']

我想要的是

if sick[i] == sick[i+1], don't appned value

所以我想要的结果是

sick=['J02', 'J20', 'A08', 'J45','A08'] <-- this isn't removing duplicates. I just don't want to append "if sick[i] == sick[i+1]"

我该怎么办？

Answer 1

我的建议：

for datum in data :
    if not datum in sick:
        sick.append(datum)

Answer 2

您可以使用以下

data = ['J02', 'J02', 'J20', 'J20', 'J20', 'J20', 'J20', 'A08', 'J45']
sick=[]

for datum in data:
    if datum not in data:
       sick.append(datum)

这将给出输出：

['J02', 'J20', 'A08', 'J45']

Answer 3

如果应该允许重复，那么这将起作用：

for datum in data:
    if len(sick) == 0 or sick[-1] != datum:
        sick.append(datum)

不在list -python中追加重复项

3 个答案: