Question

我正在使用quickblox进行申请。此应用程序适用于Android iOS。我正在努力推送通知。为此，我使用此代码：

// Send push to users with ids 292,300,1295
    QBMEvent *event = [QBMEvent event];
    event.notificationType = QBMNotificationTypePush;
    event.usersIDs = [NSString stringWithFormat:@"%ld", (long)recepID];
    event.type = QBMEventTypeOneShot;

    // standart parameters
    // read more about parameters formation http://quickblox.com/developers/Messages#Use_custom_parameters
    //
    NSMutableDictionary  *dictPush = [NSMutableDictionary  dictionary];
    [dictPush setObject:@"Message received from Bob" forKey:@"message"];
    [dictPush setObject:@"5" forKey:@"ios_badge"];
    [dictPush setObject:@"mysound.wav" forKey:@"ios_sound"];

    // custom params
    [dictPush setObject:@"234" forKey:@"user_id"];
    [dictPush setObject:@"144" forKey:@"thread_id"];

    NSError *error = nil;
    NSData *sendData = [NSJSONSerialization dataWithJSONObject:dictPush options:NSJSONWritingPrettyPrinted error:&error];
    NSString *jsonString = [[NSString alloc] initWithData:sendData encoding:NSUTF8StringEncoding];
    //
    event.message = jsonString;

    [QBRequest createEvent:event successBlock:^(QBResponse * _Nonnull response, NSArray<QBMEvent *> * _Nullable events)
    {
        // Successful response with event
        NSLog(@"Create event successfully to: %ld", (long)recepID);
    }
                errorBlock:^(QBResponse * _Nonnull response)
    {
        // Handle error
        NSLog(@"Create event error to: %@", response.error.description);
    }];

此创建事件失败，并显示此错误：

Create event error to: 
   Error reasons:{
    errors =     (
        "No one can receive the message"
    );
}

所有设备都在子目录部分。还是它给出了错误。我从this quickblox document复制了此代码。请帮帮我。

Answer 1

通过在我的代码中添加以下代码解决了这个问题：

event.isDevelopmentEnvironment = ![QBApplication sharedApplication].productionEnvironmentForPushesEnabled;

Quickblox通用推送通知无效。

1 个答案: