Question

我需要将结果集值加上＆＃34; |＆＃34;在循环内部例如。一组值10 | 2,6 | 2,8 | 1应该导致24 | 5。

这是我的代码：

<?php
 $fromdate="2016-03-31";
 $todate="2016-03-31";
 $TAG="1";
 $con = mysqli_connect("XXXXX","XX","XXX","XXX");
 $query = mysqli_query($con, "CALL sp_Android_Online_Dashboard('$fromdate', '$todate','$TAG')") or die("Query fail: " . mysqli_error());
 $Totfiles = 0;
 $file_minutes = 0;
 $Tot_minutes=0;
 $Pending=0;
 while(($row = mysqli_fetch_array($query))) 
 {
     $Totfiles +=$row["Totfiles"];
     $file_minutes +=$row["file_minutes"];
     $Pending =str_replace(array("/"),"|",$row["Pending"]); //need to sum all the values separated by "|"
     $Tot_minutes +=$row["Tot_minutes"];
 }
$response["Details"]['Totfiles'] = $Totfiles;
$response["Details"]['file_minutes'] = $file_minutes;
$response["Details"]['Pending'] = $Pending;
$response["Details"]['Tot_minutes'] = $Tot_minutes;
echo json_encode($response);      
?>

$row["Pending"] contains the values which are to be summed

现在结果，

"Pending":"16|9"
"Pending":"11|3"
"Pending":"6|2"

我的预期结果，

"Pending":"33|14"

Answer 1

这就是你的目标，我认为，你首先创建一个包含2个值的数组，在每次迭代中通过循环向它们添加新值，最后你可以将它再次内爆成一个字符串

// Start with an array containing 0 twice
$Totalpending = [0,0];
 while(($row = mysqli_fetch_array($query))) 
 {
     // On each loop we add the left value to the first value in the array and the right value to the second value in the array
     $tmp = explode("|", $row['Pending']);
     $Totalpending[0] += $tmp[0];
     $Totalpending[1] += $tmp[1];

     $Totfiles +=$row["Totfiles"];
     $file_minutes +=$row["file_minutes"];
     $Pending =str_replace(array("/"),"|",$row["Pending"]); //need to sum all the values separated by "|"
     $Tot_minutes +=$row["Tot_minutes"];
 }
// if you want to format the values in the same way again, although an array is much easier to handle, but it's up to you.
$stringTotalpending = implode('|',$Totalpending);

您想要的字符串值将位于$stringTotalpending

Answer 2

首先，我们需要从$row["Pending"]爆炸值。

$arr = explode("|", $row["Pending"]);

现在使用循环添加这两个数字：

$temp = 0;
for($i = 0; $i < count($arr); $i++){
    $temp += (int) $arr[$i];
}

现在$temp将包含结果。

就这么简单。

_{另外，作为旁注，您的代码容易受到SQL注入攻击。}

Answer 3

用'|'评估相同的字符串怎么样？替换为'+'？

eval('$result = ' . str_replace('|', '+', preg_replace('/[^0-9|]/', '', $row["Pending"])) . ';');
echo "$result\n";

注意preg_replace（）来清理输入。如果输入已经消毒，则可以避免

php总结由特殊字符

3 个答案: