Question

我在sed中指定“{”和“}”之间的地址空间，所以我希望只将第一个“Acer”替换为“TTTT”。第二个是不期望的。我该如何解决这个问题？我在Ubuntu 15.10上测试过，sed版本是sed（GNU sed）4.2.2。

提前致谢。

$ echo "
[
    {
        \"manufacturer\": \"Acer\",
        \"regularPrice\": 165.99,
    },
    [
        \"manufacturer\": \"Acer\",
        \"regularPrice\": 165.99,
    ],
    {
        \"manufacturer\": \"Acer\",
        \"regularPrice\": 165.99,
    }
]
" | sed "/{/,/},/ {s/\"Acer\"/\"TTTT\"/}"

其结果如下：

[
  {
    "manufacturer": "TTTT",
    "regularPrice": 165.99,
  },
  [
    "manufacturer": "Acer",
    "regularPrice": 165.99,
  ],
  {
    "manufacturer": "TTTT",
    "regularPrice": 165.99,
  }
]

Answer 1

这仅适用于GNU sed

sed "/{/,/},/ {0,/\"Acer\"/ s/\"Acer\"/\"TTTT\"/}"

或更确切地说，以下内容也在起作用

sed "/{/,/},/ {0,/\"Acer\"/s//\"TTTT\"/}"

Answer 2

echo '
[
    {
        "manufacturer": "Acer",
        "regularPrice": 165.99,
    },
    [
        "manufacturer": "Acer",
        "regularPrice": 165.99,
    ],
    {
        "manufacturer": "Acer",
        "regularPrice": 165.99,
    }
]
' | perl -0777 -pe 's/({[^}]*)"Acer"([^{]*?},)/$1"TTTT"$2/gs'

我在这里使用了perl v5.16.3，它返回以下内容：

[
    {
        "manufacturer": "TTTT",
        "regularPrice": 165.99,
    },
    [
        "manufacturer": "Acer",
        "regularPrice": 165.99,
    ],
    {
        "manufacturer": "Acer",
        "regularPrice": 165.99,
    }
]

注意：

-0777诋毁整个文件
-p循环划线并打印
-e命令行中的代码
全局替换（s ///）（g）并允许通配符匹配换行符（

sed - “{”和“}”之间的地址空间

2 个答案: