Question

我似乎无法让这个程序运行。没有错误，当我运行它时，什么都没有显示出来。任何帮助表示赞赏1

#Return multiple values

def load():
    name=input("enter a name")
    num1=int(input("Enter num1: "))
    num2=int(input("Enter num2: "))
    num3=int(input("Enter num3: "))
    return name, num1, num2, num3

def calc(num1, num2, num3):
    sum=num1, num2, num3
    avg=sum/3
    return sum, avg

def output(name, num1, num2, num3, avg, sum):
    print("Your name is: ", name)
    print("The 3 numbers are: ", num1, num2, num3)
    print('The sum is: ',sum )
    print("The average is: ", avg)

def main():
    name, num1, num2, num3=load()
    sum, avg=calc(num1, num2, num3)
    output(name, num1, num2, num3, sum, avg)

Answer 1

你需要调用main()函数，这一行可能会抛出异常：

sum=num1, num2, num3
avg=sum/3

将其更改为：

sum=num1 + num2 + num3
avg=sum/3

Answer 2

作为前面提到的友好评论者，你没有调用你的main（）例程（参见最后一行）。您还在sum的签名中混合了avg和output次调用的序列。此外，sum是Python内置函数。避免那些。我使用了raw_input，因为我使用的是Python 2.x，请不要让您感到困惑。我对Python 2.x的使用也是你在我的输出中看到额外括号的原因。总的来说，你非常接近一个有效的解决方案，对初学者来说很好！

#Return multiple values

def load():
    name=raw_input("enter a name: ")
    num1=int(raw_input("Enter num1: "))
    num2=int(raw_input("Enter num2: "))
    num3=int(raw_input("Enter num3: "))
    return name, num1, num2, num3

def calc(num1, num2, num3):
    sum1=num1+num2+num3  # sum is a python keyword
    avg=sum1/3.0 # avoiding integer division in case you are using python 2.x
    return sum1, avg

def output(name, num1, num2, num3,   sum1, avg):
    print("Your name is: ", name)
    print("The 3 numbers are: ", num1, num2, num3)
    print('The sum is: ',sum1 )
    print("The average is: ", avg)

def main():
    name, num1, num2, num3=load()
    sum1, avg=calc(num1, num2, num3)
    output(name, num1, num2, num3, sum1,avg)

main()

输出：

enter a name: Anton
Enter num1: 1
Enter num2: 2
Enter num3: 3
('Your name is: ', 'Anton')
('The 3 numbers are: ', 1, 2, 3)
('The sum is: ', 6)
('The average is: ', 2.0)

需要帮助找到总和和平均值

2 个答案: