Question

我有一个SQL查询，用于显示在指定日期范围内按天创建的工作订单数量。当我查询单个日期范围时，例如3/1/2016到2016年3月31日，它很有效。

SELECT DATEADD(dd, DATEDIFF(dd, 0, dateCreated), 0) the_date,
COUNT(*) work_order_count
FROM WorkOrder
where active = 1 and
dateCreated >= '3/1/2016' and
dateCreated <= '3/31/2016 23:59:59'
GROUP BY DATEADD(dd, DATEDIFF(dd, 0, dateCreated), 0)
order by 1;

我想进一步采取相同的查询，以便我可以查询相同的数据，但显示多个日期范围的结果。我的具体目的是为前一年的比较并排显示数据。理想情况下，我想显示在2014年，2015年和2016年为3 / 1-3 / 31创建的工作订单数量，但都在同一视图/结果中。

这可能吗？我已经查看了连接，但它们似乎是在你使用不同的表时，而不是同一个表。

Answer 1

只需使用条件聚合（或支点）：

SELECT CAST(dateCreated as DATE) as the_date,
       SUM(CASE WHEN YEAR(dateCreated) = 2014 THEN 1 ELSE 0 END) as cnt_2014,
       SUM(CASE WHEN YEAR(dateCreated) = 2015 THEN 1 ELSE 0 END) as cnt_2015,
       SUM(CASE WHEN YEAR(dateCreated) = 2016 THEN 1 ELSE 0 END) as cnt_2016
FROM WorkOrder
WHERE active = 1 and
      MONTH(dateCreated) = 3 and
      YEAR(dateCreated) in (2014, 2015, 2016)
GROUP BY CAST(dateCreated as DATE)
ORDER BY the_date;

Answer 2

使用数据透视表：

;with cte1 as (
  select dateCreated, datepart(year, dateCreated) as Y
  from WorkOrder
  where datepart(month, dateCreated) = 3 and datepart(day, dateCreated) between 5 and 25
)
SELECT *
FROM cte1
  PIVOT
  (
    count(dateCreated)
    FOR Y in ([2014], [2015], [2016])
  ) as pv

Answer 3

如下：

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Answer 4

SELECT datepart(dd, 'yyyy'), datepart(dd, 'MM'), datepart(dd, 'dd'),
       COUNT(*) work_order_count
FROM WorkOrder
where active = 1 
  and dateCreated >=  '3/1/2016' 
  and dateCreated <   '4/1/2020' 
GROUP BY datepart(dd, 'yyyy'), datepart(dd, 'MM'), datepart(dd, 'dd')     
order by datepart(dd, 'yyyy'), datepart(dd, 'MM'), datepart(dd, 'dd');

SQL Query显示相同的数据，但基于同一视图中的不同日期

4 个答案: