Question

我该怎么做？我有这张桌子

╔════════╦══════════╦══════════╗
║ item   ║ price    ║ date     ║
╠════════╬══════════╬══════════╣
║ Dollar ║       60 ║ 1.3.2016 ║
║ Dollar ║       50 ║ 2.3.2016 ║
║ Bound  ║      100 ║ 1.3.2016 ║
║ Bound  ║      110 ║ 2.3.2016 ║
║ Euro   ║      600 ║ 1.3.2016 ║
║ Euro   ║      580 ║ 3.3.2016 ║
╚════════╩══════════╩══════════╝

输出应显示每种类型的一个项目，最后一个日期的最终价格为dedepnding，前一行的价格差异如下：

╔════════╦══════════╦════════════════════════╗
║ item   ║ price    ║ date     ║ differnece  ║
╠════════╬══════════╬════════════════════════╣
║ Dollar ║       50 ║ 2.3.2016 ║   -10       ║
║ Bound  ║      110 ║ 2.3.2016 ║    10       ║
║ Euro   ║      580 ║ 3.3.2016 ║   -20       ║
╚════════╩══════════╩════════════════════════╝

我这样做了......

SELECT item,date,price FROM wpdatatable_23 WHERE date IN (SELECT max(date) FROM wpdatatable_23 GROUP BY item LIMIT 0,1) group by item

......它工作正常。我只是不知道如何做差异的事情，有什么帮助吗？

Answer 1

您可以使用相关子查询来计算差异：

SELECT item, `date`, price,
       price - (SELECT price
                FROM wpdatatable_23 AS t2
                WHERE t2.item = t1.item AND t2.`date` < t1.date 
                ORDER BY t2.`date` DESC LIMIT 0,1) AS difference
FROM wpdatatable_23 AS t1 
WHERE date IN (SELECT max(date) 
               FROM wpdatatable_23 
               GROUP BY item )

Answer 2

检查一下（Giorgos SQL的小修改）：

SELECT
    a.item,
    a.`date`,
    a.price,
    a.price  - (SELECT price
                FROM prices AS t2
                WHERE t2.item = a.item AND t2.`date` < a.`date` 
                ORDER BY t2.`date` DESC LIMIT 0,1) as diff
FROM
    prices AS a
WHERE
    a.date = (SELECT MAX(date) FROM prices b WHERE b.item = a.item GROUP BY item);

同一个表，按类型分组最大日期，2行差异

2 个答案: