Question

我想在控制器中加入两个表..

paginate模型也有很多条件，但我想在这里简化它。

$Table = $this->Table->query('
 SELECT Table.id FROM Table
                INNER JOIN TableA ON Table.id = TableA.table_id
                INNER JOIN TableA.Table_id = TabelB.id
                WHERE 
                IFNULL(Table.x,0) <> 0
                GROUP BY Table.id
                HAVING COUNT(*) > 1');


$this->paginate = array(
'paramType' => 'querystring'
,'joins' => $Table
    )           
);

我对Cake感到满意，更多来自SQL背景，但这可以在控制器中完成，还是应该在模型中进行？

Answer 1

    $UserId = $this->Auth->user(id);
$this->Rate->bindModel(array('belongsTo'=>array('Vehicle'=>array('className'=>'Vehicle','foreignKey'=>'vehicle_id'),),),false);

   $this->paginate = array('conditions'=>array('Rate.user_id'=>$UserId),
                        'order'     => array('Rate.created DESC'),
                        'limit'     =>'2'
                          );     
  $rating =  $this->paginate('Rate');

Answer 2

正如我在“控制器分页与子查询”中回答的问题一样，这个问题的回答是相同的

$this->paginate = array(
'paramType' => 'querystring',
'joins' => array(
    array(
    'table' => '(SELECT Table.id
                FROM Table 
                INNER JOIN TableA ON Table.id = TableA.Table_id
                INNER JOIN TableB ON TableA.TableB_id = TableB.id
                WHERE 
                1 = 1
                GROUP BY Table.id
                HAVING COUNT(*) = 1)'
        'alias' => 'Table_x',
        'type' => 'INNER',
        'conditions' => array('Table_x.id = Table.id')
        )
    )
);


$Table = $this->paginate();

在分页中加入两个模型

2 个答案: