如何检查另一个数组中是否存在数组键的值？

Question

我可以这样做：

filter(lambda x: x.key1 in ["aa", "bb", "cc"], [{key1: ..., key2: ...}, {key1: ...}])

我怎么能做相反的事情？

dict_items = [{key1: ..., key2: ...}, {key1: ...}]
filter(lambda x: x in ???dict_items.key1???, ["aa", "bb", "cc"])

Answer 1

假设您有两个dicts d1 = {key1: val1, key2: val2}和d2 = {key3: val3, key4: val4}

目前尚不清楚您要比较的是什么，但如果您想要比较键，请输入：

set.intersection(set(d1.keys()), set(d2.keys()))

对于值：

set.intersection(set(d1.values()), set(d2.values()))

Answer 2

use可以使用list comprehension如下：

a = {"aa":1, "ll":4}
b = {"bb": 'pl', "xx":12, "qq": 66}
print [key for j in [a, b] for key, val in j.iteritems() if key in ["aa", "bb", "cc"]]

或者如果您只需要钥匙，可以使用：

print [key for j in [a, b] for key in j.keys() if key in ["aa", "bb", "cc"]]

输出：

['aa', 'bb']