我有一个问题：我在html头中有一个函数，然后在正文中我有一个表单类型提交并运行onsubmit函数。它看起来我无法达到功能或去功能向数据库插入细节。我无法完成这个想法。请帮帮我。
<?php
function sida() {
$host = "localhost";
$username = "root";
$password = "";
$databasename = "vinhcv_truonghoc";
$connect = mysql_connect($host, $username, $password);
$db = mysql_select_db($databasename);
if (isset($_POST['comment']) && isset($_POST['name'])) {
$comment = $_POST['comment'];
$name = $_POST['name'];
$q = "insert into comments values('', '$name', '$comment', CURRENT_TIMESTAMP)";
echo $q;
$insert = mysql_query($q);
if (!$insert) { echo mysql_error(); }
$id = mysql_insert_id($insert);
$select = mysql_query("select name, comment, post_time from comments where name = '$name' and comment='$comment' and id='$id'");
if ($row = mysql_fetch_array($select)) {
$name = $row['name'];
$comment = $row['comment'];
$time = $row['post_time'];
?>
<div class="comment_div">
<p class="name">Posted By:<?php echo $name;?></p>
<p class="comment"><?php echo $comment;?></p>
<p class="time"><?php echo $time;?></p>
</div>
<?php
}
exit;
}
}
?>
和身体中的形式：
<form method="POST" onsubmit="sida()">
<textarea id="comment" placeholder="Write Your Comment Here....."></tetarea>
<br>
<input type="text" id="username" placeholder="Your Name">
<br>
<input type="submit" value="Post Comment">
</form>
<div id="all_comments">
<?php
$host = "localhost";
$username = "root";
$password = "";
$databasename = "vinhcv_truonghoc";
$connect = mysql_connect($host,$username,$password);
$db = mysql_select_db($databasename);
$comm = mysql_query("select name,comment,post_time from comments order by post_time desc");
while($row = mysql_fetch_array($comm))
{
$name = $row['name'];
$comment = $row['comment'];
$time = $row['post_time'];
?>
<div class="comment_div">
<p class="name">Posted By:<?php echo $name;?></p>
<p class="comment"><?php echo $comment;?></p>
<p class="time"><?php echo $time;?></p>
</div>
<?php
}
?>
</div>
在正文中它可以连接到数据库来获取信息，这意味着在连接数据库时没有错误，那么为什么它不能插入数据库呢？
答案 0 :(得分：1)
您需要做的是评论： -
<form method="POST" ><!-- remove onsubmit="sida()"-->
<textarea id="comment" placeholder="Write Your Comment Here....." name = "comment"></textarea><!-- add name attribute -->
<br>
<input type="text" id="username" placeholder="Your Name" name = "username"><!-- add name attribute -->
<br>
<input type="submit" value="Post Comment">
</form>
<div id="all_comments">
<?php
$data = array(); // define empty array
if(isset($_POST["comment"]) && isset($_POST["username"])){ // check with posted value not button value
$host="localhost";
$username="root";
$password="";
$databasename="vinhcv_truonghoc";
$i = 0; // DEFINE COUNTER
$connect=mysqli_connect($host,$username,$password,$databasename); // mysql_* is deprecated so use mysqli_* or PDO
if($connect){ // IF CONNECTION ESTABLISHED
$comment = mysqli_real_escape_string($connect,$_POST['comment']); // Prevent from SQL Injection
$username = mysqli_real_escape_string($connect,$_POST['username']); // Prevent from SQL Injection
$query = mysqli_query ($connect,"INSERT INTO comments (username,comment) VALUES ('".$username."','".$comment."')"); // check and change table name as well as column name
if($query){
echo "Inserted Successfully";
}else{
echo "Problem occur in insertion because of".mysqli_error($connect);
}
$comm = mysqli_query($connect,"select name,comment,post_time from comments order by post_time desc");
if($comm){ // IF QUERY EXECUTED
while($row=mysqli_fetch_array($comm)){
$data[$i]["name"] = $row['name']; // ASSIGN VALUES TO THE ARRAY
$data[$i]["comment"] = $row['comment'];
$data[$i]["time"] = $row['post_time'];
$i++;
}
}else{
echo "Query execution failed because of".mysqli_error($connect);
}
}else{
echo'connection problem because of'.mysqli_connect_error();
}
}else{
echo "All fields are need to fill properly";
}
?>
<?php foreach ($data as $dat){?> <!-- ITERATE THROUGH ARRAY -->
<div class="comment_div">
<p class="name">Posted By:<?php echo $data['name'];?></p>
<p class="comment"><?php echo $data['comment'];?></p>
<p class="time"><?php echo $data['time'];?></p>
</div>
<?php } ?>
</div>
答案 1 :(得分：0)
好像你没有将任何参数传递给$_POST数组。您需要将name属性传递给输入字段。由于您要运行PHP服务器端功能，因此需要使用action属性。
像这样：
<form method="POST" action="sida()">
<textarea name="comment" id="comment" placeholder="Write Your Comment Here....."></textarea>
<br>
<input name="name" type="text" id="username" placeholder="Your Name">
<br>
<input type="submit" value="Post Comment" name="submit">
</form>
答案 2 :(得分：0)
$host="localhost";
$username="root";
$password="";
$databasename="vinhcv_truonghoc";
function connect() {
global $host,$username,$password,$databasename;
$con=mysql_connect($host,$username,$password) or die ("ConnectionFailed");
mysql_select_db($databasename,$con) or exit ("Failed to connect");
return $con; }
function iud($query) //Insert,Update,Delete {
$con=connect();
$result=mysql_query($query,$con);
$n=mysql_affected_rows($con);
mysql_close($con);
return $n; }
function select ($query) //Select {
$con=connect();
$result=mysql_query($query,$con);
mysql_close($con); return $result; }
if(isset($_REQUEST['submit'])) {
$name=$_REQUEST['name'];
$comment=$_REQUEST['comment'];
$query="INSERT INTO `comments`(`name`, `comment`, `post_time`)
VALUES('$name','$comment',CURRENT_TIMESTAMP)";
$n=iud($query);
echo $n; }
?>
<html> <head></head> <body> <form method="GET"> <table>
<tr> <td>Name</td> <td><Input type="text" name="name" id=""
class="" placeholder="Name.."></td> </tr>
<tr> <td>Comment</td> <td><textarea name="comment" rows="5" cols="40" placeholder="Comment
Here.."> </textarea></td> </tr>
<tr> <td></td> <td><Input type="submit" name="submit" id="" class="" value="submit">
</td> </tr>
</table> </form>
<!-- Showing Result --> <table> <?php $query="Select * from comments ORDER BY coid DESC"; //Coid Is A Primary Key
$result=select($query); $n=mysql_num_rows($result); if($n>0) {
while($data=mysql_fetch_array($result)) extract($data); } ?>
<tr> <td><?php echo @$name; ?></td> </tr> <tr> <td><?php
echo @$comment; ?></td> </tr> </table>
</body> </html>
我希望它对你有用：）