Question

我在stackoverflow中阅读了很多文章，但我仍然无法进行排序。

这种情况是这样的：

我有一个9列没有标题的csv文件，如下所示：

D,0000001,2016/01/01 01:00,111,0.000,0000008,10.000,NET,Computer
B,0000002,2016/01/01 01:30,111,0.000,0000001,10.000,NET,Computer
C,0000003,2016/01/01 02:00,121,0.000,0000001,10.000,ORG,Computer
E,0000001,2016/01/01 02:00,121,0.000,0000003,10.000,ORG,Computer
E,0000001,2016/01/01 02:00,121,0.000,0000003,10.000,COM,Computer
C,0000001,2016/01/01 02:00,121,0.000,0000002,10.000,COM,Computer

我想要的输出是2（000001），6（0000008），8（NET）列的顺序，并输出到新的csv文件，如下所示：

C,0000001,2016/01/01 02:00,121,0.000,0000002,10.000,COM,Computer
E,0000001,2016/01/01 02:00,121,0.000,0000003,10.000,COM,Computer
E,0000001,2016/01/01 02:00,121,0.000,0000003,10.000,ORG,Computer
D,0000001,2016/01/01 01:00,111,0.000,0000008,10.000,NET,Computer
B,0000002,2016/01/01 01:30,111,0.000,0000001,10.000,NET,Computer
C,0000003,2016/01/01 02:00,121,0.000,0000001,10.000,ORG,Computer

我尝试了一些这样的代码但不起作用：

@echo off
setlocal

for /F "tokens=1-9 delims=," %%a in (input.csv) do set a[%%b,%%a,%%c,%%d,%%e,%%f,%%g,%%h,%%i] =%%
for /F "tokens=2-10 delims=[,]=" %%a in ('set a[') do echo %%b,%%a,%%c,%%d,%%e,%%f,%%g,%%h,%%i

有人可以帮助我吗？我是键入命令脚本的新手。

Answer 1

你的方法非常好。只是字段值的顺序设置不正确，无法获得输出所需的排序顺序。

@echo off
if not exist input.csv goto :EOF
setlocal
for /F "tokens=1-9 delims=," %%a in (input.csv) do set "a[%%b,%%f,%%h,%%a,%%c,%%d,%%e,%%g,%%i]=%%"
del input.csv
for /F "tokens=2-10 delims=[,]=" %%a in ('set a[') do echo %%d,%%a,%%e,%%f,%%g,%%b,%%h,%%c,%%i>>input.csv
endlocal

此处使用%%b,%%f,%%h,%%a,%%c,%%d,%%e,%%g,%%i而不是%%b,%%a,%%c,%%d,%%e,%%f,%%g,%%h,%%i创建环境变量，当然在输出时也需要%%d,%%a,%%e,%%f,%%g,%%b,%%h,%%c,%%i而不是%%b,%%a,%%c,%%d,%%e,%%f,%%g,%%h,%%i。

Answer 2

你几乎拥有它：

@echo off
setlocal

for /F "tokens=1-9 delims=," %%a in (input.csv) do set "a[%%b%%f%%h]=%%a,%%b,%%c,%%d,%%e,%%f,%%g,%%h,%%i"
for /F "tokens=2 delims==" %%a in ('set a[') do echo %%a

但是，您显示的结果是 not ，如您在问题中所述。如果您想要%%f字段下的逆序，您可以使用：

@echo off
setlocal EnableDelayedExpansion
for /F "tokens=1-9 delims=," %%a in (input.csv) do (
   set /A "invF=100000000-1%%f"
   set "a[%%b!invF!%%h]=%%a,%%b,%%c,%%d,%%e,%%f,%%g,%%h,%%i"
)
for /F "tokens=2 delims==" %%a in ('set a[') do echo %%a

使用命令将csv文件按三列排序？

2 个答案: