如何在弹出菜单中自定义menuItem?我需要第一个menuitem的开关。这是我到目前为止所得到的:
menu.xml文件
<menu xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:app="http://schemas.android.com/apk/res-auto"
xmlns:tools="http://schemas.android.com/tools"
tools:context="android.oli.com.fitnessapp.activities.LiveSelectActivity">
<item
android:icon="@drawable/ic_access_alarm_white_24dp"
android:orderInCategory="100"
app:showAsAction="always"
android:visible="true"
android:title="@string/action_settings"
android:onClick="showPopup"/>
</menu>
menu_popup.xml
<?xml version="1.0" encoding="utf-8"?>
<menu xmlns:android="http://schemas.android.com/apk/res/android">
<item
android:id="@+id/one"
android:title="One"/>
<item
android:id="@+id/setTime"
android:title="Two"
android:onClick="showTimePickerDialog"/>
</menu>
活动摘要
public void showPopup(MenuItem menuItem){
View view = findViewById(R.id.action_alarm);
PopupMenu popup = new PopupMenu(this, view);
MenuInflater inflater = popup.getMenuInflater();
inflater.inflate(R.menu.menu_popup, popup.getMenu());
popup.show();
}
答案 0 :(得分:18)
您可以使用popupwindow,因为它允许使用自定义布局。
ImageView
并在ur活动中实现此方法:
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
tools:context=".MainActivity"
android:padding="5dp">
<Switch
android:id="@+id/mySwitch"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_alignParentLeft="true"
android:layout_alignParentTop="true"
android:layout_marginTop="20dp"
android:text="Play with the Switch" />
<TextView
android:id="@+id/switchStatus"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_alignParentLeft="true"
android:layout_below="@+id/mySwitch"
android:layout_marginTop="22dp"
android:text="Medium Text"
android:textAppearance="?android:attr/textAppearanceMedium" />
</RelativeLayout>