Question

我有这个错误

错误：（27,57）错误：未报告的异常异常;必须抓住或宣布被抛出

在这一行：

public String encrypted = MCrypt.bytesToHex( mcrypt.encrypt("Text to Encrypt") );

并尝试用try和catch试图围绕它，但它没有用。

package com.example.user.test14;

import android.app.Activity;
import android.os.AsyncTask;
import android.os.Bundle;
import android.util.Log;


import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.message.BasicNameValuePair;
import org.apache.http.protocol.HTTP;
import org.json.JSONException;
import org.json.JSONObject;

import java.io.BufferedReader;
 import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.List;
public class MainActivity extends Activity {
MCrypt mcrypt = new MCrypt();
public String encrypted = MCrypt.bytesToHex( mcrypt.encrypt("Text to Encrypt") );

@Override
protected void onCreate(Bundle savedInstanceState) {

    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    new MyTask().execute();
}

private class MyTask extends AsyncTask<String, String, Boolean> {
    @Override
    protected void onPreExecute() {
        super.onPreExecute();
    }

    @Override
    protected Boolean doInBackground(String... params) {
        List<NameValuePair> params1 = new ArrayList<NameValuePair>();
        params1.add(new BasicNameValuePair("id","1"));
        params1.add(new BasicNameValuePair("temp",encrypted));
        params1.add(new BasicNameValuePair("pulse","sheri"));
        params1.add(new BasicNameValuePair("motion","a"));
        String link="http://192.168.0.21/insert_data.php";
        boolean success = false;
        try {

            JSONObject json = makeHttpRequest(link, "POST", params1);
            success = json.getBoolean("success");

        } catch (Exception e) {
            // TODO: handle exception
        }

        return success;
    }

    @Override
    protected void onPostExecute(Boolean result) {
        super.onPostExecute(result);
        if (result ) {
            Log.e("result","true");
        } else {
            Log.e("result","false");
        }
    }
}

private JSONObject makeHttpRequest(String url, String method,List<NameValuePair> params) {
    InputStream is = null;
    JSONObject jObj = null;
    String json = "";
    DefaultHttpClient httpClient = new DefaultHttpClient();
    HttpPost httpPost = new HttpPost(url);
    try {
        httpPost.setEntity(new UrlEncodedFormEntity(params));

        HttpResponse httpResponse = httpClient.execute(httpPost);
        HttpEntity httpEntity = httpResponse.getEntity();
        is = httpEntity.getContent();
    } catch (Exception e1) {
        // TODO Auto-generated catch block
        e1.printStackTrace();
    }

    try {
        BufferedReader reader = new BufferedReader(new InputStreamReader(is, HTTP.UTF_8), 8);
        StringBuilder sb = new StringBuilder();
        String line = null;
        while ((line = reader.readLine()) != null) {
            sb.append(line + "\n");
        }
        is.close();
        json = sb.toString();
    } catch (Exception e) {
        Log.e("Buffer Error", "Error converting result " + e.toString());
    }

    // try parse the string to a JSON object
    try {
        Log.e("json", json);
        jObj = new JSONObject(json);
    } catch (JSONException e) {
        Log.e("JSON Parser", "Error parsing data " + e.toString());
    }

    // return JSON String
    return jObj;
}
}

任何人都可以帮忙吗？我很感激。

Answer 1

将以下构造函数添加到您的类

MCrypt mcrypt;
public String encrypted;
public MainActivity(){
  try{
    mcrypt = new MCrypt();
    encrypted = MCrypt.bytesToHex( mcrypt.encrypt("Text to Encrypt") );
  } catch(Exception e){
    e.printStackTrace();
  }
}

通过替换两条相应的行。

Answer 2

如果你想用try-catch包围它，代码需要在构造函数中。或者这样做：

public class MainActivity extends Activity {
    public String encrypted = bytesToHex();

    private static String bytesToHex() {
        try {
            MCrypt mcrypt = new MCrypt();
            return MCrypt.bytesToHex(mcrypt.encrypt("Text to Encrypt"));
        }
        catch (Exception e) {
            e.printStackTrace();
            return null;
        }
    }

添加加密代码时出现未报告异常时出错

2 个答案: