Question

我应该如何编写仅以“YES”显示内部列值的查询？

Hospital_ID  MATERINITY  ENT  DERMATOLOGY  ORTHOPEDICS  
          1  YES         NO   NO           NO   
          2  YES         YES  NO           NO   
          3  YES         YES  NO           YES

我正在寻找的结果是Hospital_ID“3”：

Hospital_ID  MATERINITY  ENT  ORTHOPEDICS  
          3  YES         YES  YES

不会显示值为“NO”的列。

Answer 1

尝试

SELECT * 
FROM TableName 
WHERE MATERINITY = "YES" AND 
      DERMATOLOGY = "YES" AND 
      ORTHOPEDICS = "YES"

Answer 2

好吧，如果您只是想在排除皮肤科专栏时将其排除在外，并且您不关心任何其他列是否为NO（除非它们都是NO），那么它将是：

SELECT Hospital_ID, MATERNITY, ENT, ORTHOPEDICS,
FROM DepartmentTable
WHERE DERMATOLOGY = 'NO' AND (MATERNITY = 'YES' OR ENT = 'YES' OR ORTHOPEDICS = 'YES');

这只会给你DERMATOLOGY为NO的行，但是有另一列的值为'YES'。我假设您不希望所有列都为“否”的结果。

Answer 3

您在尝试删除列时会遇到麻烦，尤其是当您包含多家医院时。我建议将yes表示为带有联合查询的行，然后您可以在报表中交叉表。

SELECT Hospital_ID, 'MATERNITY' Dept FROM myTable t WHERE t.MATERNITY='YES'
UNION SELECT Hospital_ID, 'ENT' Dept FROM myTable t WHERE t.ENT='YES'
UNION SELECT Hospital_ID, 'DERMATOLOGY' Dept FROM myTable t WHERE t.DERMATOLOGY='YES'
UNION SELECT Hospital_ID, 'ORTHOPEDICS' Dept FROM myTable t WHERE t.ORTHOPEDICS='YES'

如果您需要过滤医院id = 3，请执行以下操作：

SELECT Hospital_ID, Dept FROM (
SELECT Hospital_ID, 'MATERNITY' Dept FROM myTable t WHERE t.MATERNITY='YES'
UNION SELECT Hospital_ID, 'ENT' Dept FROM myTable t WHERE t.ENT='YES'
UNION SELECT Hospital_ID, 'DERMATOLOGY' Dept FROM myTable t WHERE t.DERMATOLOGY='YES'
UNION SELECT Hospital_ID, 'ORTHOPEDICS' Dept FROM myTable t WHERE t.ORTHOPEDICS='YES') x
WHERE Hospital_ID=3

SQL显示特定列

3 个答案: