我在我的代码中使用了drag和drope jquery ui。代码工作正常。但是用户应该有能力在保存后编辑数据。这意味着当用户再次打开页面时,我需要恢复拖动和下垂位置。我尝试使用触发器,但我无法模仿"放弃ui"我该怎么办?
$( ".draggable-children-username" ).draggable({
snap: ".draggable-in-box",
opacity: 0.7,
revert: 'invalid',
helper: "clone"
});
$(".draggable-in-box").droppable({
accept: $(".draggable-children-username"),
hoverClass: "dropHover",
drop: function (ev, ui) {
$(this).trigger("DopeEvent", ui);
}
});
$( ".draggable-in-box" ).bind("DopeEvent", function(event, ui ){
console.log(ui);
var me = ui.draggable.clone()
ui.draggable.draggable("disable")
me.appendTo(this)
.addClass("newClass");
me.draggable({
accept: ".draggable-in-box",
revert: function(valid) {
if(!valid) {
this.remove();
$(".dr-children-id-"+this.attr("data-id")).draggable("enable");
}
}
});
});
$( ".draggable-in-box" ).trigger("DopeEvent", $( ".dr-children-id-140" ));
当前错误:未捕获TypeError:ui.draggable.clone不是函数
答案 0 :(得分:1)
一些修复。我认为您正在尝试做的工作示例:
http://jsfiddle.net/Twisty/vjGY4/125/
<强> JQuery的强>
<?php echo "<a href='attendance_add.php'>" . $row['emp_name'] . "</a> "; ?>
$(".draggable-children-username").draggable({
snap: ".draggable-in-box",
opacity: 0.7,
revert: 'invalid',
helper: "clone"
});
$(".draggable-in-box").droppable({
accept: $(".draggable-children-username"),
hoverClass: "dropHover",
drop: function(ev, ui) {
$(this).trigger("DopeEvent", ui.draggable);
}
});
$(".draggable-in-box").bind("DopeEvent", function(event, ui) {
console.log(ui);
var me = $(ui).clone();
//ui.draggable.draggable("disable")
me.appendTo(this)
.addClass("newClass");
me.draggable({
accept: ".draggable-in-box",
revert: function(valid) {
if (!valid) {
this.remove();
$(".dr-children-id-" + this.attr("data-id")).draggable("enable");
}
}
});
});
$(".draggable-in-box").trigger("DopeEvent", $(".dr-children-id-140"));
中传递了可拖动对象或jquery对象。使用DopeEvent
var me = $(ui).clone();
中,您需要传递这样的元素:drop
希望有所帮助。您可以通过检查传递的内容来改善您的活动。像$(this).trigger("DopeEvent", ui.draggable);
之类的东西可以起作用。