我制作了一个使用Google Places API的应用程序。点击一个地方后,它会返回公司名称,地址和MainActivity的编号。当我点击号码时,我可以打开拨号器,但我似乎无法将MainActivity上返回的号码输入到拨号器中。关于如何做到这一点的任何想法。感谢
我的代码如下
MainActivity
private TextView mName;
private TextView mAddress;
private TextView mNumber;
private static final LatLngBounds Sligo = new LatLngBounds(
new LatLng(54.27, -8.47), new LatLng(54.27, -8.47));
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.content_main);
mName = (TextView) findViewById(R.id.textView);
mAddress = (TextView) findViewById(R.id.textView2);
mAttributions = (TextView) findViewById(R.id.textView3);
mNumber = (TextView) findViewById(R.id.textView4);
Button pickerButton = (Button) findViewById(R.id.pickerButton);
pickerButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
try {
PlacePicker.IntentBuilder intentBuilder =
new PlacePicker.IntentBuilder();
intentBuilder.setLatLngBounds(Sligo);
List<Integer> filterTypes = new ArrayList<Integer>();
filterTypes.add(Place.TYPE_CAR_REPAIR);
Intent intent = intentBuilder.build(MainActivity.this);
startActivityForResult(intent, PLACE_PICKER_REQUEST );
} catch (GooglePlayServicesRepairableException
| GooglePlayServicesNotAvailableException e) {
e.printStackTrace();
}
}
});
@Override
protected void onActivityResult(int requestCode,
int resultCode, Intent data) {
if (requestCode == PLACE_PICKER_REQUEST
&& resultCode == Activity.RESULT_OK) {
final Place place = PlacePicker.getPlace(this, data);
final CharSequence name = place.getName();
final CharSequence address = place.getAddress();
final CharSequence formatted_phone_number = place.getPhoneNumber();
// final CharSequence car = place.TYPE_CAR_REPAIR();
//public abstract List<Integer> getTypeFilter(place.TYPE_CAR_REPAIR);
String attributions = (String) place.getAttributions();
if (attributions == null) {
attributions = "";
}
mName.setText(name);
mAddress.setText(address);
mAttributions.setText(Html.fromHtml(attributions));
mNumber.setText(formatted_phone_number);
} else {
super.onActivityResult(requestCode, resultCode, data);
}
onClick事件
public void onClickNumber(View arg)
{
Intent intent = new Intent(Intent.ACTION_DIAL);
startActivity(intent);
}
答案 0 :(得分:14)
试试这个
String phone = mNumber.getText().toString();
Intent phoneIntent = new Intent(Intent.ACTION_DIAL, Uri.fromParts(
"tel", phone, null));
startActivity(phoneIntent);
答案 1 :(得分:2)
试试这个。
String number = "494498498";
Intent intent = new Intent(Intent.ACTION_DIAL);
intent.setData(Uri.parse("tel:" +number));
startActivity(intent);