Question

我想在Arduino程序中运行循环三次以使led闪烁3次。如何运行循环3次并退出loop.how以在循环中使用return语句？一旦领先，持续1秒然后下车。

int LedPin = 13;
int Loops = 1;
void setup() {

  pinMode(LedPin, OUTPUT);
}

void loop() {
digitalWrite(13, LOW);
Loops = Loops + 1;
  if    ( Loops < 3 )

  {
      digitalWrite(13, HIGH);
      delay(2000);  
    }

 else  {
  digitalWrite(13, LOW);      
  exit(0);  
  }
}

Answer 1

arduino循环永远循环。

https://www.arduino.cc/en/Reference/Loop

如果你想停止运行那个循环，你可以将arduino置于睡眠模式：

http://playground.arduino.cc/Learning/ArduinoSleepCode

我还建议您彻底了解流量控制的工作原理（以及可能的状态机）。请参阅第5章。控制结构：

https://www.arduino.cc/en/Tutorial/BuiltInExamples

Answer 2

如果我们＆＃34;展开＆＃34; loop函数，我们得到：

// Loops is 1 on the first call.
digitalWrite(13, LOW);
Loops = Loops + 1;
// Loops is now 2
if (Loops < 3)
{
    // So, we enter here...
    digitalWrite(13, HIGH);
    delay(2000);  
}
else
{
    // but not here
    digitalWrite(13, LOW);      
    exit(0);  
}
// Next call:
// Turn off the light.
digitalWrite(13, LOW);
Loops = Loops + 1;
// Loops is now 3
if (Loops < 3)
{
    // So we don't enter here
    digitalWrite(13, HIGH);
    delay(2000);  
}
else
{
    // but we enter here
    digitalWrite(13, LOW);      
    // Which exits
    exit(0);  
}

所以你打开LED一次，然后将其关闭然后退出如果您调整循环计数器，您将关闭LED，然后立即再次打开它，这样看起来会更长时间。

您可能希望在每个循环上执行完整的开/关循环 - 如下所示：

int LedPin = 13;
int Loops = 0;

void setup() {
    pinMode(LedPin, OUTPUT);
    digitalWrite(LedPin, LOW);
}

void loop() {
    Loops = Loops + 1;
    if (Loops <= 3)
    {
        digitalWrite(LedPin, HIGH);
        delay(2000);
        digitalWrite(LedPin, LOW);
        delay(2000);
    }
    else
    {
        exit(0);  
    }
}

Answer 3

void setup() {
  // initialize digital pin 13 as an output.


  for (int i=0; i < 4 ; i++) 
  {
    pinMode(13, OUTPUT);
    digitalWrite(13, HIGH); 
     delay(1000); 
     digitalWrite(13, LOW);    // turn the LED off by making the voltage LOW
      delay(1000);    

  }

}

// the loop function runs over and over again forever
void loop() {

}

Answer 4

int LedPin = 13;

void setup() {
pinMode(LedPin, OUTPUT);
function() ;       //call this function whatever you want
}

void function()
{
digitalWrite(LedPin, HIGH);
delay(1000)       //add the desired delay
digitalWrite(LedPin, LOW);
delay(1000)     //add the desired delay
digitalWrite(LedPin, HIGH);
delay(1000)       //add the desired delay
digitalWrite(LedPin, LOW);
delay(1000)     //add the desired delay
digitalWrite(LedPin, HIGH);
delay(1000)       //add the desired delay
digitalWrite(LedPin, LOW);
delay(1000)     //add the desired delay

}

在Arduino程序中无法闪烁3次

4 个答案: