Question

是否可以打印＆＃34; no＆＃34;如果没有找到结果

SELECT mobileno,  
 CASE
    WHEN region = '1234' 
    THEN 'Yes'
    ELSE 'NO'
  END  
FROM subscriber
WHERE region = '1234'
and  status = 1
and mobileno in (77777,88888)

目前只打印1行，如

77777，是

但我想跟随

77777,yes
88888,no

更新：如果我们删除区域条件，则一个mobileno（如7777）可能属于两个区域，那么7777将获得打印，NO和YES将在两行中打印。

样本数据

sr.No, Name, mobileno, region, status
1,     abc,  77777,    1234,    1
2,     xyz,  88888,    1222,    1
3,     tyu,  22342,    9898,    1
4,     abc,  77777,    8787,    1

Sample OutPut

77777, Yes
88888, No

Answer 1

你可以创造＆＃39;通过选择双重和左连接来表：

SELECT t.dummy_num,
       CASE WHEN s.mobileno is null then 'No' else 'Yes' end
FROM (SELECT 77777 as dummy_num from dual
      UNION select 88888 from dual) t
LEFT JOIN subscriber s
 ON(t.dummy_num = s.mobileno and s.region = '1234' and s.status = 1 )

编辑：您也可以像这样动态地执行：

SELECT t.mobileno,
       CASE WHEN s.mobileno is null then 'No' else 'Yes' end
FROM (select distinct mobileno from subscriber) t
LEFT JOIN subscriber s
 ON(t.mobileno= s.mobileno and s.region = '1234' and s.status = 1 )
WHERE t.mobileno IN(777,888,.....)

如果SELECT语句没有结果，则使用CASE标记否

1 个答案: