Question

我的数据需要在网络图中可视化。我正在尝试使用D3，我设法得到静态图。

有人可以建议我如何创建图表，当点击节点A时，它将扩展到与节点A相关的其他节点。

这是我当前的代码（从D3库中的示例编辑）：

<!DOCTYPE html>
<meta charset="utf-8">
<style>

.link {
  fill: none;
  stroke: #666;
  stroke-width: 1.5px;
}

.node circle {
  fill: #ccc;
  stroke: #fff;
  stroke-width: 1.5px;
}

text {
  font: 10px sans-serif;
  pointer-events: none;
}

</style>
<body>
<script src="//d3js.org/d3.v3.min.js"></script>
<script>

// http://blog.thomsonreuters.com/index.php/mobile-patent-suits-graphic-of-the-day/
var links = [
  {source: "Plant B", target: "Round shape"},
  {source: "Library", target: "Plant C"},
  {source: "Library", target: "Plant A"},
  {source: "Plant C", target: "Sandy"},
  {source: "Round shape", target: "Plant A"},
  {source: "Plant C", target: "Long shape"},
  {source: "Plant A", target: "Round shape"},
  {source: "Plant D", target: "Lake"},
  {source: "Plant D", target: "Round shape"},
  {source: "Plant A", target: "Library"},
  {source: "Plant B", target: "Library"},
  {source: "Plant E", target: "Lake"},
  {source: "Lake", target: "Sandy"},
  {source: "Plant E", target: "Long shape"},
  {source: "Library", target: "Wet soil"},
  {source: "Library", target: "Plant B"}
];

var nodes = {};

// Compute the distinct nodes from the links.
links.forEach(function(link) {
  link.source = nodes[link.source] || (nodes[link.source] = {name: link.source});
  link.target = nodes[link.target] || (nodes[link.target] = {name: link.target});
});

var width = 960,
    height = 500;

var force = d3.layout.force()
    .nodes(d3.values(nodes))
    .links(links)
    .size([width, height])
    .linkDistance(80)
    .charge(-300)
    .on("tick", tick)
    .start();

var svg = d3.select("body").append("svg")
    .attr("width", width)
    .attr("height", height);

var link = svg.selectAll(".link")
    .data(force.links())
  .enter().append("line")
    .attr("class", "link");

var node = svg.selectAll(".node")
    .data(force.nodes())
  .enter().append("g")
    .attr("class", "node")
    .on("mouseover", mouseover)
    .on("mouseout", mouseout)
    .call(force.drag);

node.append("circle")
    .attr("r", 8);

node.append("text")
    .attr("x", 12)
    .attr("dy", ".35em")
    .text(function(d) { return d.name; });

function tick() {
  link
      .attr("x1", function(d) { return d.source.x; })
      .attr("y1", function(d) { return d.source.y; })
      .attr("x2", function(d) { return d.target.x; })
      .attr("y2", function(d) { return d.target.y; });

  node
      .attr("transform", function(d) { return "translate(" + d.x + "," + d.y + ")"; });
}

function mouseover() {
  d3.select(this).select("circle").transition()
      .duration(750)
      .attr("r", 16);
}

function mouseout() {
  d3.select(this).select("circle").transition()
      .duration(750)
      .attr("r", 8);
}

</script>

我的数据应该是来自查询，所以有什么方法可以将该节点链接到我的查询页面吗？

使用D3进行网络图可视化

0 个答案: