Question

我正在调用API获取以下json数据

[{"id":"1","start_time":"07:30 AM","end_time":"11:00 AM","status":"1"},{"id":"2","start_time":"11:00 AM","end_time":"02:00 PM","status":"1"},{"id":"3","start_time":"02:00 PM","end_time":"05:00 PM","status":"1"},{"id":"4","start_time":"05:00 PM","end_time":"08:30 AM","status":"1"},{"id":"5","start_time":"09:00 PM","end_time":"11:00 PM","status":"1"},{"id":"6","start_time":"11:00 PM","end_time":"01:30 AM","status":"1"},{"id":"7","start_time":"01:30 AM","end_time":"07:30 AM","status":"1"}]

start_time = 07：30 AM ，没关系但是当我 start_time = 11:00 AM（零分钟）时，我想将其显示为 start_time = 11 AM 。
I have marked the zero minutes here in output

如果分钟大于零，则显示它们否则用冒号（:)标志隐藏它们 我该怎么做？

Answer 1

function reduceTime(obj, prop) {
    var colon_index = obj.indexOf(':');
    if(obj[prop][colon_index + 1] == '0' && obj[prop][colon_index + 2] == '0') {
        return obj[prop].slice(0, colon_index + 1);
    }   
    return obj[prop];
}

用法：

obj = reduceTime(obj, 'start_time');

Answer 2

    timeSlot=[];
    function reduceTime(st, et) {
        var obj={
            start_time:'',
            end_time:''
        };
        if (st.indexOf(":00")>0){
            obj.start_time=st.replace(":00", "")
        }else{
            obj.start_time=st;
        }
        if (et.indexOf(":00")>0){
            obj.end_time=et.replace(':00', '')
        }else{
            obj.end_time=et;
        }
        timeSlot.push(obj)
    }

用法：

for(i=0;i<response.length;i++){
                reduceTime(response[i].start_time, response[i].end_time)
            }
            $scope.timeSlot=timeSlot;

然后我们将得到一个对象数组。

从零值angularjs的时间开始删除分钟部分

2 个答案: