我需要帮助我的显示图像，显示是正确的，但我不知道为什么图像不出现。
CREATE TABLE `images` (
`id` int(11) NOT NULL,
`name` varchar(100) DEFAULT NULL,
`size` int(11) DEFAULT NULL,
`type` varchar(20) DEFAULT NULL,
`content` mediumblob
) ENGINE=MyISAM DEFAULT CHARSET=latin1;
这是我的“ upload.php ”
<?php
// Check for post data.
if ($_POST && !empty($_FILES)) {
$formOk = true;
//Assign Variables
$path = $_FILES['image']['tmp_name'];
$name = $_FILES['image']['name'];
$size = $_FILES['image']['size'];
$type = $_FILES['image']['type'];
if ($_FILES['image']['error'] || !is_uploaded_file($path)) {
$formOk = false;
echo "Error: Error in uploading file. Please try again.";
}
//check file extension
if ($formOk && !in_array($type, array('image/png', 'image/x-png', 'image/jpeg', 'image/pjpeg', 'image/gif'))) {
$formOk = false;
echo "Error: Unsupported file extension. Supported extensions are JPG / PNG.";
}
// check for file size.
if ($formOk && filesize($path) > 500000) {
$formOk = false;
echo "Error: File size must be less than 500 KB.";
}
if ($formOk) {
// read file contents
$content = file_get_contents($path);
//connect to mysql database
if ($conn = mysqli_connect('localhost', 'root', '', 'upload')) {
$content = mysqli_real_escape_string($conn, $content);
$sql = "insert into images (name, size, type, content) values ('{$name}', '{$size}', '{$type}', '{$content}')";
if (mysqli_query($conn, $sql)) {
$uploadOk = true;
$imageId = mysqli_insert_id($conn);
} else {
echo "Error: Could not save the data to mysql database. Please try again.";
}
mysqli_close($conn);
} else {
echo "Error: Could not connect to mysql database. Please try again.";
}
}
}
?>
<html>
<head>
<title>Upload image to mysql database.</title>
<style type="text/css">
img{
margin: .2em;
border: 1px solid #555;
padding: .2em;
vertical-align: top;
}
</style>
</head>
<body>
<?php if (!empty($uploadOk)): ?>
<div>
<h3>Image Uploaded:</h3>
</div>
<div>
<img src="image.php?id=<?=$imageId ?>" width="150px">
<strong>Embed</strong>: <input size="25" value='<img src="image.php?id=<?=$imageId ?>">'>
</div>
<hr>
<?php endif; ?>
<form action="<?=$_SERVER['PHP_SELF']?>" method="post" enctype="multipart/form-data" >
<div>
<h3>Image Upload:</h3>
</div>
<div>
<label>Image</label>
<input type="hidden" name="MAX_FILE_SIZE" value="500000">
<input type="file" name="image" />
<input name="submit" type="submit" value="Upload">
</div>
</form>
</body>
</html>
然后这是我的“ image.php ”
<?php
// verify request id.
if (empty($_GET['id']) || !is_numeric($_GET['id'])) {
echo 'A valid image file id is required to display the image file.';
exit;
}
$imageId = $_GET['id'];
//connect to mysql database
if ($conn = mysqli_connect('localhost', 'root', '', 'upload')) {
$content = mysqli_real_escape_string($conn, $content);
$sql = "SELECT type, content FROM images where id = {$imageId}";
if ($rs = mysqli_query($conn, $sql)) {
$imageData = mysqli_fetch_array($rs, MYSQLI_ASSOC);
mysqli_free_result($rs);
} else {
echo "Error: Could not get data from mysql database. Please try again.";
}
//close mysqli connection
mysqli_close($conn);
} else {
echo "Error: Could not connect to mysql database. Please try again.";
}
if (!empty($imageData)) {
// show the image.
header("Content-type: {$imageData['type']}");
echo $imageData['content'];
}
?>
每次我尝试上传图片时都会成功，但我上传的图片没有显示。但这只出现图像错误。请有人帮我吗？
或者有没有人可以给我一个如何使用数据库上传和显示图像的教程？
答案 0 :(得分：0)
<?php
error_reporting( ~E_NOTICE );
require_once 'dbconfig.php';
if(isset($_GET['edit_id']) && !empty($_GET['edit_id']))
{
$id = $_GET['edit_id'];
$stmt_edit = $DB_con->prepare('SELECT userName, userProfession, userPic FROM
tbl_users
WHERE userID =:uid');
$stmt_edit->execute(array(':uid'=>$id));
$edit_row = $stmt_edit->fetch(PDO::FETCH_ASSOC);
extract($edit_row);
}
else
{
header("Location: index.php");
}
if(isset($_POST['btn_save_updates']))
{
$username = $_POST['user_name'];// user name
$userjob = $_POST['user_job'];// user email
$imgFile = $_FILES['user_image']['name'];
$tmp_dir = $_FILES['user_image']['tmp_name'];
$imgSize = $_FILES['user_image']['size'];
if($imgFile)
{
$upload_dir = 'user_images/'; // upload directory
$imgExt = strtolower(pathinfo($imgFile,PATHINFO_EXTENSION)); // get image extension
$valid_extensions = array('jpeg', 'jpg', 'png', 'gif'); // valid extensions
$userpic = rand(1000,1000000).".".$imgExt;
if(in_array($imgExt, $valid_extensions))
{
if($imgSize < 5000000)
{
unlink($upload_dir.$edit_row['userPic']);
move_uploaded_file($tmp_dir,$upload_dir.$userpic);
}
else
{
$errMSG = "Sorry, your file is too large it should be less then 5MB";
}
}
else
{
$errMSG = "Sorry, only JPG, JPEG, PNG & GIF files are allowed.";
}
}
else
{
// if no image selected the old image remain as it is.
$userpic = $edit_row['userPic']; // old image from database
}
// if no error occured, continue ....
if(!isset($errMSG))
{
$stmt = $DB_con->prepare('UPDATE tbl_users
SET userName=:uname,
userProfession=:ujob,
userPic=:upic
WHERE userID=:uid');
$stmt->bindParam(':uname',$username);
$stmt->bindParam(':ujob',$userjob);
$stmt->bindParam(':upic',$userpic);
$stmt->bindParam(':uid',$id);
if($stmt->execute()){
?>
<script>
alert('Successfully Updated ...');
window.location.href='index.php';
</script>
<?php
}
else{
$errMSG = "Sorry Data Could Not Updated !";
}
}
}
?>
答案 1 :(得分：-1)
您必须暂时提取['content']。像这样：
$rs = mysqli_query($conn, $sql);
while ( $imageData = mysqli_fetch_assoc($rs) ) {
$content = $imageData['content'];
}
header("Content-type: $content ");
echo $content;
我会建议您检查和更改：
$sql = "SELECT type, content FROM images where id = {$imageId}";
代表
$sql = "SELECT type, content FROM images where id = '$imageId' ";