有人可以帮我把这个arduino代码翻译成python代码吗?
#define BUFFLEN 3
byte buffer[] = { 0x05, 0x0D, 0x02, 0xFF, 0x10, 0xAA }
for (byte i=0; i < BUFFLEN; i++) {
val = analogRead(A0);
val = constrain(val,0,1023);
buffer[i*2] = (byte)(i<<2) | highByte(val);
buffer[i*2+1] = lowByte(val);
}
由于
答案 0 :(得分:0)
您可以使用pyserial库通过串口捕获数据,然后使用python处理数据,在这种情况下,以下代码可以执行:
import serial
import struct
ser = serial.Serial('COM6',9600) #put the port number and the communication rate
BUFFLEN = 3 #constant
buffer = [ 0x05, 0x0D, 0x02, 0xFF, 0x10, 0xAA ] #array
i=0 #initialize control variable
def clamp(n, minn, maxn):
return max(min(maxn, n), minn)
while (i < BUFFLEN):
val = ser.read()
val = clamp(val,0,1023)
buffer[i*2] = (i<<2) or struct.pack('<h', val)
buffer[i*2+1] = struct.pack('>h', val)
i+=1 #increment
但请记住从arduino IDE中捕获并打印数据到序列号