甜甜圈图表python

时间:2016-03-29 22:17:39

标签: python matplotlib pie-chart

所以我使用这段代码创建了一个带有python的圆环图(灵感来自这个Donut情节recipe):

def make_pie(sizes, text,colors,labels):
    import matplotlib.pyplot as plt
    import numpy as np

    col = [[i/255. for i in c] for c in colors]

    fig, ax = plt.subplots()
    ax.axis('equal')
    width = 0.35
    kwargs = dict(colors=col, startangle=180)
    outside, _ = ax.pie(sizes, radius=1, pctdistance=1-width/2,labels=labels,**kwargs)
    plt.setp( outside, width=width, edgecolor='white')

    kwargs = dict(size=20, fontweight='bold', va='center')
    ax.text(0, 0, text, ha='center', **kwargs)
    plt.show()

c1 = (226,33,7)
c2 = (60,121,189)

make_pie([257,90], "Gender (AR)",[c1,c2],['M','F'])

导致:

enter image description here

我的问题是,现在我想要各自的百分比。为此,我只是添加了论点:

autopct='%1.1f%%'
像这样:

kwargs = dict(colors=col, startangle=180,autopct='%1.1f%%')

但这会导致以下错误:

Traceback (most recent call last):
  File "draw.py", line 30, in <module>
    make_pie([257,90], "Gender (AR)",[c1,c2],['M','F'])
  File "draw.py", line 13, in make_pie
    outside, _ = ax.pie(sizes, radius=1, pctdistance=1-width/2,labels=labels,**kwargs)
ValueError: too many values to unpack

那么,我做错了什么?

1 个答案:

答案 0 :(得分:3)

来自docstring:

If *autopct* is not *None*, return the tuple (*patches*,
  *texts*, *autotexts*), where *patches* and *texts* are as
  above, and *autotexts* is a list of
  :class:`~matplotlib.text.Text` instances for the numeric
  labels.

因此,如果您想使用pie()解包autopct的结果,则需要3个值:

kwargs = dict(colors=col, startangle=180, autopct='%1.1f%%')
outside, _, _ = ax.pie(sizes, radius=1, pctdistance=1-width/2,
                       labels=labels,**kwargs)

或者如果没有解压缩它可能会更强大,所以它可以使用或不使用autopct

outside = ax.pie(sizes, radius=1, pctdistance=1-width/2,
                 labels=labels,**kwargs)[0]