我试图用contextmanager隐藏一些try / except复杂性。这是一个简单的例子:
from contextlib import contextmanager
import mpd
mpdclient = mpd.MPDClient()
mpdclient.connect("localhost", 6600)
@contextmanager
def mpdcontext():
try:
yield
except mpd.ConnectionError:
mpdclient.connect("localhost", 6600)
with mpdcontext():
mpdclient.status()
with mpdcontext():
mpdclient.lsinfo()
现在,正如我所理解的那样,在调用yield时执行with语句中的块。在我的情况下,如果这引发异常,我重新连接到mpd。重新连接后,我可以以某种方式再次执行with-block吗?
由于
答案 0 :(得分:6)
简短的回答是你不能从上下文管理器中得到两次。您可以考虑使用装饰器来包装您尝试执行的内容,并在放弃之前重试并重新连接一定次数。这是一个简单的(非生产用途)示例,仅用于说明:
import mpd
import functools
HOST = "localhost"
PORT = 6600
mpdclient = mpd.MPDClient()
mpdclient.connect(HOST, PORT)
def withreconnect(retries=1):
def _wrapper(func):
@functools.wraps(func)
def wrapped(*args, **kwargs):
for _ in range(retries + 1): # Loop retries + first attempt
try:
return func(*args, **kwargs)
except mpd.ConnectionError:
mpdclient.connect(HOST, PORT)
return _wrapped
return wrapped
@withreconnect() # Reconnect 1 time, default
def status():
mpdclient.status()
@withreconnect(retries=3) # Reconnect 3 times
def lsinfo():
mpdclient.lsinfo()
编辑:在无参数情况下添加对装饰器的调用