Question

我有一个对象数组。如果我做一个console.log，我可以看到这些对象数组。

[Object, Object, Object, Object,Object]
[0-4]
0:Object
    Name: Nikhil
    User_ID:123 
    admin:true
    read:false
    write:false
1:Object
    Name:andy
    User_ID:124
    admin:false
    read:true
    write:false
2:Object
    Name:Nik
    User_ID:125
    admin:false
    read:false
    write:true
3:Object
    Name:ranea
    User_ID:126
    admin:false
    read:false
    write:true 
4:Object
    Name:isha
    User_ID:127
    admin:false
    read:true
    write:false

现在，如果我做JSON.stringify，我得到这个输出。

[{"Name":"Nikhil","User_ID":"123","admin":true,"read":false,"write":false},
{"Name":"andy","User_ID":"124","admin":false,"read":true,"write":false},
{"Name":"Nik","User_ID":"125","admin":false,"read":false,"write":true},         
{"Name":"ranea","User_ID":"126","admin":false,"read":false,"write":true},
{"Name":"isha","User_ID":"127","admin":false,"read":true,"write":false}]

我没有对所有参数进行字符串化，而是只想做很少的事情。对于例如我不想传递姓名。我只想传递User_ID，因为它是唯一的，以及admin，read，write属性。

如何使用loadash创建新的对象数组，然后对结果进行字符串化。我在JSON.stringify之后的最终输出应该是这样的

[{"User_ID":"123","admin":true,"read":false,"write":false},
{"User_ID":"124","admin":false,"read":true,"write":false},
{"User_ID":"125","admin":false,"read":false,"write":true},         
{"User_ID":"126","admin":false,"read":false,"write":true},
{"User_ID":"127","admin":false,"read":true,"write":false}]

Answer 1

使用Libre Office documentation应该是：

 var newArr = _.map(oldArray,
  function(item) {
    return _.pick(item, ['User_ID', 'admin', 'read', 'write']);
  });

Answer 2

您可以使用Array.map()功能。

var obj = [ { "Name": "Christophe", "Age": 42, "foo": "bar" }, { "Name": "Blah", "Age": 42, "foo": "foo2" }]
var filtered = obj.map(function (element) {
    return {
        "Name": element.Name
    }
});

之后，filtered包含您的对象，其中只包含您要保留的密钥，您可以JSON.stringify。

console.log(JSON.stringify(filtered));
// [ {"Name": "Christophe"}, {"Name": "Blah"} ]

Answer 3

您可以使用此小功能返回新阵列。

var arr = [{
  Name: "Nikhil",
  User_ID: "123",
  admin: "true",
  read: "false",
  write: "false"
}, {
  Name: "andy",
  User_ID: "124",
  admin: "false",
  read: "true",
  write: "false"
}];

function returnArr(array) {
  var arrNew = arr;
  for (let in arrNew) {
    delete arrNew[let].Name;
  }
  return JSON.stringify(arrNew);
}

document.write(returnArr(arr)); // or console.log(returnArr(arr))

传递对象数组中的某些参数

3 个答案: