Question

目前我正在尝试部署用C ++编写的网络应用程序，看起来它由于网络问题而陷入无限循环：

[isaev@feck-5 ~]$ sudo strace -p 26252 -f -e trace=network -s 10000 
[pid 26272] getpeername(30, 0x7f1699ddfb60, [28]) = -1 ENOTCONN (Transport endpoint is not connected)
[pid 26272] getpeername(30, 0x7f1699ddfb60, [28]) = -1 ENOTCONN (Transport endpoint is not connected)
[pid 26272] getpeername(30, 0x7f1699ddfb60, [28]) = -1 ENOTCONN (Transport endpoint is not connected)
[pid 26272] getpeername(30, 0x7f1699ddfb60, [28]) = -1 ENOTCONN (Transport endpoint is not connected)
[pid 26272] getpeername(30, 0x7f1699ddfb60, [28]) = -1 ENOTCONN (Transport endpoint is not connected)
[pid 26272] getpeername(30, 0x7f1699ddfb60, [28]) = -1 ENOTCONN (Transport endpoint is not connected)
[pid 26272] getpeername(30, 0x7f1699ddfb60, [28]) = -1 ENOTCONN (Transport endpoint is not connected)

我需要知道应用程序缺少哪种网络连接。

假设我可以使用gdb附加到流程，如何打印truct sockaddr *指向的0x7f1699ddfb60（man getpeername）变量的值？

Answer 1

你可以＆＃34;垂头丧气＆＃34;并通过执行

取消引用指针（或其值）

(gdb) p *((struct sockaddr_in_or_whichever_you_use *) pointer_to_struct_sockaddr)

或

(gdb) p *((struct sockaddr_in_or_whichever_you_use *) 0x7f1699ddfb60)

gdb：print sockaddr指针值

1 个答案: