IndentationError:预期python中的缩进块(使用硬标签)

时间:2016-03-29 16:14:05

标签: python tabs atom-editor

我已经检查并仔细检查了我的代码是否正确使用标签进行缩进而不是看起来像标签的空格。我在Max OS X上使用原子代码编辑器。关于选项卡的设置如下:

  • 取消选中软标签
  • 标签大小设置为4
  • 标签类型设置为硬

这是我的代码:

#Password Cracker test program
#Program written by Zach Hofmeister, ported to Python
#READ THE README BEFORE USING ANY OF MY CODE!!!

#Below variable saves the password entered by the user. Only compared to a complete password to simulate brute-force cracking.
userPassword = raw_input("Enter a 4 digit password for the computer to guess. Only Upper/Lower case letters and numbers.") + ""

#The following variable contains an array of all the possible characters that can be present.
possibleCharacters = ['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z','a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z','1','2','3','4','5','6','7','8','9','0']

#The default computer guess.
computerGuess = 'AAAA'

#Establishes that the computer has not correctly guessed the password, will be changed when password is discovered.
correctGuess = False

#The following variable keeps track of how many guesses it takes for the computer to crack the password.
totalGuesses = 0

#The following variable keeps track of what character is currently being tested.
i = [0,0,0,0,0,0,0,0,0,0]

#Function that compares the current guess to the user input. Notice that the password isn't guessed letter by letter, the whole 4 character guess is generated.
def checkPassword(passwordGuess):
    if (passwordGuess == userPassword):
        print "Your password is " + computerGuess + "."
        print "Took " + totalGuesses + " tries to guess your password."
    else:
        #print "Guessing again."

#Function that creates the current guess and compares it to the actual password.
def charGuess(charNumberDigit):
    computerGuess = computerGuess[0:charNumberDigit - 1] + possibleCharacters[i[charNumberDigit - 1]] + computerGuess[charNumberDigit:end]
    checkPassword(computerGuess)
    if (charNumberDigit != 4):
        i[charNumberDigit] = 0
    i[charNumberDigit - 1] += 1
    totalGuesses += 1

#The loop that tells the computer to try a guess
while (computerGuess != userPassword):
    while (i[3] <= 61 && computerGuess != userPassword):
        charGuess(4)
        while (i[2] <= 61 && i[3] == 61 && computerGuess != userPassword):
            charGuess(3)
            while (i[1] <= 61 && i[2] == 61 && computerGuess != userPassword):
                charGuess(2)
                while (i[0] <= 61 && i[1] === 61 && computerGuess != userPassword):
                    charGuess(1)

顺便说一下,我已经阅读了有关此问题的其他帖子,但他们没有解决我的问题,因为(据我所知)我正在使用标签而不是标签和空格的混合。

1 个答案:

答案 0 :(得分:2)

在Python中,代码块中总会存在某些东西。您已在checkPassword函数中注释掉了else块。

def checkPassword(passwordGuess):
    if (passwordGuess == userPassword):
        print "Your password is " + computerGuess + "."
        print "Took " + totalGuesses + " tries to guess your password."
    else:
        #print "Guessing again."

如果您不想做任何事情,可以使用pass语句:

else:
    pass