Question

我试图获取此Feed的内容： http://www.institut-viavoice.com/viavoice-paris/publications/sondages-publies?format=feed&type=rss

这是我的代码：

$url = 'http://www.institut-viavoice.com/viavoice-paris/publications/sondages-publies?format=feed&type=rss';

$options = array(
CURLOPT_RETURNTRANSFER => true,
CURLOPT_HEADER         => false,
CURLOPT_FOLLOWLOCATION => true,
CURLOPT_ENCODING       => "",
CURLOPT_USERAGENT      => "Mozilla/5.0 (Windows NT 6.1; WOW64; rv:18.0) Gecko/20100101 Firefox/18.0",
CURLOPT_AUTOREFERER    => true,
CURLOPT_CONNECTTIMEOUT => 30,
CURLOPT_TIMEOUT        => 30,
CURLOPT_MAXREDIRS      => 10
);

$curl = curl_init($url); 
curl_setopt_array( $curl, $options ); 
$content = curl_exec($curl); 
curl_close($curl);

echo $content;

我尝试了很多其他CURL选项，但它没有用。由于可以通过我的浏览器访问内容，我想可以使用PHP完成。但是我的代码有什么问题？看来这个Feed的服务器有例外吗？

Answer 1

不确定，可能是您打破了cURL选项并调用了URL。这是一个简单的例子，试一试：

function get_data($url) {
    $ch = curl_init();
    $timeout = 5;
    curl_setopt($ch, CURLOPT_URL, $url);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
    curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout);
    curl_setopt($ch, CURLOPT_USERAGENT, "Mozilla/5.0 (Windows NT 6.1; WOW64; rv:18.0) Gecko/20100101 Firefox/18.0");
    $data = curl_exec($ch);
    curl_close($ch);
    return $data;
}

$content = get_data('http://www.institut-viavoice.com/viavoice-paris/publications/sondages-publies?format=feed&type=rss');

echo $content;

无法使用CURL获取Feed内容

1 个答案: