Question

我将数据库中的结果转换为JSON数组。我想随机化这个数组，因为它现在属于1,2,3,4类并且数据总是在同一行。我如何随机化它，以便从第4,2,1,3类（不一定按此顺序）中获取数据。我的代码：

$query = $handler->query('SELECT DISTINCT c.cat_description, c.cat_name, c.cat_id, q.question, q.q_id FROM `categories` c
                                        INNER JOIN `questions` q ON c.cat_id = q.cat_id ');
$records = array();
$records = $query->fetchAll(PDO::FETCH_ASSOC);
$first = array();
$second = array();
$third = array();
$query->closeCursor();
foreach($records as $k => $v){
    $first[] = array("category_name" => $v['cat_name'], "category_id" => $v['cat_id'], "category_description" => $v['cat_description'], "question_name" => $v['question'], "question_id" => $v['q_id'],  "question_answers" => array());
    $second[] = $v['question'];
}

foreach ($second as $key => $value) {
    $ques = $value;
    $qu = $handler->query("SELECT a.quest_id, a.answer, a.iscorrect, a.anser_id FROM `answers` a INNER JOIN `questions` q ON a.quest_id = q.q_id WHERE q.question = '$ques' ");
    $third = $qu->fetchAll(PDO::FETCH_ASSOC);
    foreach($third as $tk => $tv){
        $third[$tk]['answer'.($tk+1)] = $tv['answer'];
        $third[$tk]['iscorrect'.($tk+1)] = $tv['iscorrect'];
    }
    foreach ($first as $k => $v) {
        $first[$key]['question_answers'] = $third;
    }
}
function shuffle_assoc($list) { 
  if (!is_array($list)) return $list; 

  $keys = array_keys($list); 
  shuffle($keys); 
  $random = array(); 
  foreach ($keys as $key) { 
    $random[$key] = $list[$key]; 
  }
  return $random; 
}

$first = shuffle($first);

$j['quiz'] = $first;

echo json_encode($j);

我试过shuffle但它只返回true。我尝试过array_rand但它返回了密钥。我怎么能这样做？

Answer 1

shuffle()改变数组，而不是返回具有不同元素顺序的新数组。所以你需要做的就是：

shuffle($first);

而不是：

$first = shuffle($first);

在PHP中随机播放数组并不能真正改组数组

1 个答案: