Question

我正在尝试在我的数据库中插入多个值。但我找不到解决方案来做我想做的事。

我的问题是我有一系列的值，比如 ("6.40","6.50","7.00","7.10","7.20","7.30") 我希望在每行中插入这些值，如6.40将存储在一行对应的id＆＃34; 1＆＃34;。

同样＆＃34; 6.50＆＃34;将存储在＆＃34; 2＆＃34;的id中。 id将自动递增。

类似地，它将在数据库中插入值，直到数组为空。如果有人对如何解决这个问题有任何想法，请帮助我！请怀疑我。我是PHP的新手。提前谢谢。

 for ($i=0;$i < count($slot_timings1); $i++)
 { 
    $q = $this->link->prepare('INSERT INTO doctor_appointment (doctor_name,doctor_id,appointment_date,slot_name,slot_timings) VALUES (:doctor_name,:doctor_id,:appointment_date,:slot_name,slot_timings)');
    $q->execute(array(':doctor_name'=>$doctor_name,':doctor_id'=>$doctor_id, ':appointment_date'=>$appointment_date,':slot_name'=>$slot_name,':slot_timings'=‌>$slot_timings));
 } 
 $counts = $q->rowCount(); 
 return $counts;

Answer 1

尝试这样的事情。

foreach($slot_timings1 as $data)
     { 
        $q = $this->link->prepare('INSERT INTO doctor_appointment (doctor_name,doctor_id,appointment_date,slot_name,slot_timings) VALUES (:doctor_name,:doctor_id,:appointment_date,:slot_name,slot_timings)');
        $q->execute(array(':doctor_name'=>$doctor_name,':doctor_id'=>$doctor_id, ':appointment_date'=>$appointment_date,':slot_name'=>$slot_name,':slot_timings'=‌>$data));
     }

Answer 2

试试这个：

if(is_array($slot_timings1) && !empty($slot_timings1))
{
 foreach ($slot_timings1 as $slot_timing)
 { 
$q = $this->link->prepare('INSERT INTO doctor_appointment (doctor_name,doctor_id,appointment_date,slot_name,slot_timings) VALUES (:doctor_name,:doctor_id,:appointment_date,:slot_name,:slot_timings)');

 $q->execute(array(':doctor_name'=>$doctor_name,':doctor_id'=>$doctor_id, ':appointment_date'=>$appointment_date,':slot_name'=>$slot_name,':slot_timings'=>$slot_timing));
} 

return count($slot_timings1);    
}

Answer 3

if(is_array($slot_timings1)){


 sort($slot_timings1); //Sort the elements of the array in ascending

$sql = "INSERT INTO doctor_appointment (doctor_name,doctor_id,appointment_date,slot_name,slot_timings) VALUES ";

$query_val = array();
foreach($slot_timings1 as $gettime){

    $row1 = $doctor_name;
    $row2 = $doctor_id;
    $row3 = $appointment_date;
    $row4 = $slot_name;
    $row5 = $gettime;
    $query_val[] = "('$row1', '$row2', '$row3', '$row4', '$row5')";
}

$sql .= implode(',', $query_val);

mysql_query($sql) or exit(mysql_error()); 
}

Answer 4

试试这个：

for ($i=0;$i < count($slot_timings1); $i++)
 { 
$q = $this->link->prepare('INSERT INTO doctor_appointment (doctor_name,doctor_id,appointment_date,slot_name,slot_timings) VALUES (:doctor_name,:doctor_id,:appointment_date,:slot_name,slot_timings)');
 $q->execute(array(':doctor_name'=>$doctor_name,':doctor_id'=>$doctor_id, ':appointment_date'=>$appointment_date,':slot_name'=>$slot_name,':slot_timings'=‌>$slot_timings1[$i]));
} 
$counts = $q->rowCount(); 
return $counts;

使用php在数据库中插入多个值

4 个答案: