Question

我有HTML细分：

<select id="myList">
<option value="1"selected="selected">Position 1</option>
<option value="2">Position 2</option>
<option value="3">Position 3</option>
<option value="4">Position 4</option>
<option value="5">Position 5</option>
</select>
<input type="submit" id="go" value="Go to Position"></input>

提示用户选择聚光灯的位置。 JS方面包含：

var select = document.getElementById("myList");
var answer = select.options[select.selectedIndex].value;

if (answer == "1") {
    document.getElementById("go").onclick = function () { ightAtX = -1.0; lightAtZ = 0.5; };
} else if (answer == "2") {
    document.getElementById("go").onclick = function () { lightAtX = -1.0; lightAtZ = -0.5; };
} else if (answer == "3") {
    document.getElementById("go").onclick = function () { lightAtX = 0.0; lightAtZ = -0.5; };
} else if (answer == "4") {
    document.getElementById("go").onclick = function () { lightAtX = 1.0; lightAtZ = -0.5; };
} else if (answer == "5") {
    document.getElementById("go").onclick = function () { lightAtX = 1.0; lightAtZ = 0.5; };
} else {
    return; 
}

我希望用户点击“转到位置”＆＃39;按钮以改变聚光灯的位置。但是，当我单击按钮时，没有任何变化。我错过了什么？

Answer 1

您需要检查onclick函数内的选择（答案）。答案评估一次（除非没有包含更多代码），除非你告诉它，否则不会动态更新。

这样的事情：

import random
Names = ['AETHER', 'BADGED', 'BALDER', 'BANDED', 'BANTER', 'BARBER', 'BASHER'] #ect, etc

def wordlist(words):
    for index, item in enumerate(words):
        print(index, ") ", item, sep='')

available_words = random.sample(Names, 8)
one = random.choice(available_words)

print("Welcome to the Guess-The-Word Game.\nThe Password is one of these words:")
wordlist(available_words)

def Main():
    remainingGuess = 4
    while remainingGuess > 0 and False:
        wordlist(available_words)
        print("Guesses remaining: ", remainingGuess)
        userNum =  int(input("Enter guess number between 0-7: "))
        print(userNum)
        if wordlist[userNum] == one:
            win = True
            print("You are Correct")
            else: 
            print("You  incorrect")
            remainingGuess -=1
    if win == True
        break

下拉列表和按钮不起作用

1 个答案: