Question

我有一个要求，我将Date转换为一种格式到另一种格式，我得到一个不可解析的日期例外。 Class的代码粘贴在

下面

public class DateTester {

    public static void main(String[] args) {
        // TODO Auto-generated method stub

        String stringDate  = "Fri Feb 26 14:14:40 CST 2016";
        Date date = convertToDate(stringDate);
        System.out.println(date);
    }

    public static Date convertToDate(String date) {
        SimpleDateFormat sdf = new SimpleDateFormat("MM-dd-yyyy");
        Date convertedCurrentDate = null;
        try {
            convertedCurrentDate = sdf.parse(date);
        } catch (ParseException e) {
            // TODO Auto-generated catch block
            System.out.println(e.getMessage());
        }
        return convertedCurrentDate;
    }
}

Answer 1

使用以下格式：

SimpleDateFormat sdf = new SimpleDateFormat("EEE MMM dd HH:mm:ss z yyyy");

代码：

public class StackOverflowSample {
    public static void main(String[] args) {
        String stringDate  = "Fri Feb 26 14:14:40 CST 2016";
        Date date = convertToDate(stringDate);
        System.out.println(date);
    }

    public static Date convertToDate(String date) {
        SimpleDateFormat sdf = new SimpleDateFormat("EEE MMM dd HH:mm:ss z yyyy");
        Date convertedCurrentDate = null;
        try {
            convertedCurrentDate = sdf.parse(date);
        } catch (Exception e) {
            System.out.println(e.getMessage());
        }
        return convertedCurrentDate;
    }
}

来源：https://docs.oracle.com/javase/7/docs/api/java/text/SimpleDateFormat.html

编辑：如果你想返回格式为＆＃34; MM-dd-yyyy＆＃34;

的日期字符串

public static void main(String[] args) {
    String stringDate  = "Fri Feb 26 14:14:40 CST 2016";
    Date date = convertToDate(stringDate);
    SimpleDateFormat sdf = new SimpleDateFormat("MM-dd-yyyy");
    String dateFormatted = sdf.format(date);
    System.out.println(dateFormatted);
}

Java Date Parse异常

1 个答案: