Question

我的代码是

  let jsonData = try NSJSONSerialization.JSONObjectWithData(data!, options:NSJSONReadingOptions.MutableContainers ) as! NSArray
                            let json = JSON(jsonData)


for (_, subJSON): (String, JSON) in json[0]["events"] {

 let rel1 = InboxEvents(title: subJSON["title"].string!, guests: subJSON["guests"].string!, eventpic: subJSON["eventpic"].string!, eventID : NSInteger(subJSON["ID"].string!)!)


self.arrayOfRels.append(rel1)

    }

这是InboxEvents类

class InboxEvents {

    var title = ""
    var guests = ""
    var eventpic = ""
    var eventID = 6


    init(title : String, guests: String, eventpic : String, eventID : NSInteger) {

        self.title = title
        self.guests = guests
        self.eventpic = eventpic
        self.eventID = eventID

    }

我在for循环中有fatal error: unexpectedly found nil while unwrapping an Optional value。

json输出在这里

[
  {
    "events" : [
      {
        "ID" : "3",
        "title" : "Test Event",
        "guests" : 3,
        "eventpic" : "/images\/event_pic\/event1.jpg"
      },
      {
        "ID" : "1",
        "title" : "Test Event",
        "guests" : 2,
        "eventpic" : "/images\/event_pic\/event1.jpg"
      }
    ]
  }
]

这里有什么问题？

Answer 1

您的问题出现在您显示的json中的DATEDIFF()作为示例，guest参数是Int类型，但是当您获取值时，您将该值作为字符串获取
因此，当您只是打印该值时，它将显示为零，当您尝试强制打开时，它会崩溃

所以可以有两个选项

您将json guest属性更改为字符串，而不是将您作为字符串传递的InboxEvent
另一种选择是根据您的要求获取interger / dobule中的值将其转换为字符串并传入InboxEvent或使InboxEvent获取Int而不是字符串

尝试读取JSON数据时出现致命错误

1 个答案: