我跟随转换的简单类:
#include <iostream>
using namespace std;
template<int p>
class Mod {
int n;
friend Mod operator+(const Mod &x, const Mod &y) {
const int sum = x.n + y.n;
if (sum < p) {
Mod z(sum);
return z;
} else if (sum >= p) {
Mod z2(sum - p);
return z2;
}
}
operator int() {
if (p == 0) return n;
if (p == 1) return 0;
for (int r = 0; r <= abs(n); r++) {
if (((r - n) % p) == 0) {
return r;
}
}
}
friend Mod operator-(const Mod &x) {
if (x.n == 0) return 0;
Mod z(-static_cast<int>(x) + p);
return z;
}
friend std::ostream &operator<<(std::ostream &out, const Mod &x) {
out << reinterpret_cast<int>(x); // invalid cast from type ‘const Mod<5>’ to type ‘int’ out << reinterpret_cast<int>(x);
return out;
}
public:
Mod(int x) {
n = x;
}
};
int main() {
Mod<5> z(3), x(2);
cout << z + x << endl; // error: invalid cast from type ‘const Mod<5>’ to type ‘int’ out << reinterpret_cast<int>(x);
cout << z << endl; //error: invalid cast from type ‘const Mod<5>’ to type ‘int’ out << reinterpret_cast<int>(x); // invalid cast from type ‘const Mod<5>’ to type ‘int’ out << reinterpret_cast<int>(x);
cout << -x << endl; //error: invalid static_cast from type ‘const Mod<5>’ to type ‘int’ Mod z(-static_cast<int>(x) + p);
return 0;
}
当我尝试编译并运行它们时,我看到以下消息:
[ 33%] Building CXX object CMakeFiles/TestCpp.dir/main.cpp.o
/home/user/ClionProjects/TestCpp/main.cpp: In instantiation of ‘std::ostream& operator<<(std::ostream&, const Mod<5>&)’:
/home/user/ClionProjects/TestCpp/main.cpp:75:17: required from here
/home/user/ClionProjects/TestCpp/main.cpp:56:13: error: invalid cast from type ‘const Mod<5>’ to type ‘int’
out << reinterpret_cast<int>(x); // invalid cast from type ‘const Mod<5>’ to type ‘int’ out << reinterpret_cast<int>(x);
^
/home/user/ClionProjects/TestCpp/main.cpp: In instantiation of ‘Mod<5> operator-(const Mod<5>&)’:
/home/user/ClionProjects/TestCpp/main.cpp:77:14: required from here
/home/user/ClionProjects/TestCpp/main.cpp:50:36: error: invalid static_cast from type ‘const Mod<5>’ to type ‘int’
Mod z(-static_cast<int>(x) + p);
答案 0 :(得分:4)
对于static_cast,
使用隐式转换和用户定义转换的组合在类型之间进行转换。
将考虑用户定义的转化,但是您要在int
对象上转换为const
,您应该使operator int()
const成员函数:
operator int() const {
~~~~~
...
}
通过重新解释基础位模式在类型之间进行转换。
与
static_cast
不同,但与const_cast
类似,reinterpret_cast
表达式不会编译为任何CPU指令。它纯粹是一个编译器指令,它指示编译器将表达式的位序列(对象表示)视为具有new_type类型。
所以reinterpret_cast<int>(x)
无论如何都无法工作,用户定义的转化也不会被考虑。