我是c#的新手。我想知道一个字符串,如用户名是否包含特定的单词。我想从数组中获取这些特定的单词。这是一个例子。
Console.Write("Name: ");
_name = Console.ReadLine();
name = Program.ProperNameMethod( _name);
Console.WriteLine();
string[] badWordArray = { "aBadword1", "aBadWord2", "aBadWord3" };
if (!string.IsNullOrEmpty(name) // Would like to check for the badwordarray aswell)
(更新)
谢谢大家,但是我学习c#只用了大约一个月就无法覆盖lambda或regex了。我稍后会看看这些代码。
答案 0 :(得分:4)
使用以下lambda表达式查找name是否包含坏词。
bool nameHasBadWords = badWordArray.Any(p => name.Contains(p));
答案 1 :(得分:3)
这是我能做的;
// Lowered bad words array
string[] badWordArray = { "abadword1", "abadword2", "abadword3" };
bool isBadWord = false;
if (!string.IsNullOrEmpty(name))
{
name = name.ToLower();
isBadWord = badWordArray.Any(badWord => name.Contains(badWord));
}
我也测试了其他答案;
459 ms :
.Any(badWord => string.Equals(name, badWord, StringComparison.CurrentCultureIgnoreCase));
1464 ms :
.Any(badWord => name.IndexOf(badWord, StringComparison.CurrentCultureIgnoreCase) >= 0);
247 ms :
.Any(badWord => name.Contains(badWord));
这是我的简单(& stupid )测试代码:
var name = "tuckyou";
// Lowered bad words array
string[] badWordArray = { "abadword1", "abadword2", "abadword3" };
Stopwatch stopwatch = new Stopwatch();
int oneMillion = 1000000;
bool isBadWord = false;
stopwatch.Start();
for (int i = 0; i < oneMillion; i++)
{
isBadWord = badWordArray.Any(badWord => string.Equals(name, badWord, StringComparison.CurrentCultureIgnoreCase));
}
stopwatch.Stop();
Console.WriteLine(stopwatch.ElapsedMilliseconds);
stopwatch.Reset();
stopwatch.Start();
for (int i = 0; i < oneMillion; i++)
{
isBadWord = badWordArray.Any(badWord => name.IndexOf(badWord, StringComparison.CurrentCultureIgnoreCase) >= 0);
}
stopwatch.Stop();
Console.WriteLine(stopwatch.ElapsedMilliseconds);
stopwatch.Reset();
stopwatch.Start();
if (!string.IsNullOrEmpty(name))
{
name = name.ToLower();
}
for (int i = 0; i < oneMillion; i++)
{
isBadWord = badWordArray.Any(badWord => name.Contains(badWord));
}
stopwatch.Stop();
Console.WriteLine(stopwatch.ElapsedMilliseconds);
Console.ReadLine();
当然,使用stopWatch并不准确。但它提出了一个想法。
答案 2 :(得分:2)
您可能希望不区分大小写验证:
propTypes
或者,如果您在当前文化
上进行验证string[] badWordArray = { "aBadword1", "aBadWord2", "aBadWord3" };
Boolean isBadWord = badWordArray
.Any(badWord => name.IndexOf(badword, StringComparison.OrdinalIgnoreCase) >= 0);
Paranoic 案例涉及使用正则表达式,如下所示:
Boolean isBadWord = badWordArray
.Any(badWord => name.IndexOf(badWord, StringComparison.CurrentCultureIgnoreCase) >= 0);
答案 3 :(得分:0)
考虑到你说你是初学者。这是一种更简单的方法。我知道这些答案比这更好,但这对初学者来说应该是好的。
Console.Write("Name: ");
string userInput = Console.ReadLine();
//The words that you dont want your user to have
string[] array = new string[2];
array[0] = "bad";
array[1] = "reallybad";
for (int i = 0; i < array.Length; i++)
{
//Used to lower so user cant get away with stuffs like: rEALLyBAd
if (userInput.Contains(array[i].ToLower()))
{
Console.WriteLine("Invalid name!");
}
}
Console.ReadKey();