我一直在编写一个程序,它将获取一系列音乐文件的名称并播放它们。我成功地做到了这一点,但是,我想要修改一些东西,让它更好一些。我试图让音乐以随机顺序播放,但在整个列表播放之前不重复播放任何歌曲。我几乎能够做到,但我认为我的do-while循环有问题。该程序按预期运行大约八首歌曲,但随后它停止播放音乐,JVM继续运行。我正在使用BlueJ,因为我仍然是AP Comp Sci学生,所以我意识到我可能无法完成这项任务,但任何帮助将不胜感激。我有一个驱动程序,“MusicDriver”,它与另外两个类别“有一个”关系:“MP3”和“音乐”。
我的MP3课程:
import java.io.BufferedInputStream;
import java.io.FileInputStream;
import javazoom.jl.player.Player;
public class MP3 {
String filename;
Player player;
public void stopMP3() { if (player != null) player.close(); }
// play the MP3 file to the sound card
public void playMP3(String filename) {
try {
FileInputStream fis = new FileInputStream(filename);
BufferedInputStream bis = new BufferedInputStream(fis);
player = new Player(bis);
}
catch (Exception e) {
System.out.println("Problem playing file " + filename);
System.out.println(e);
}
// run in new thread to play in background
new Thread() {
public void run() {
try { player.play(); }
catch (Exception e) { System.out.println(e); }
}
}.start();
}
}
我的音乐课程:
import java.util.*;
public class Music{
private ArrayList<String> music;
public Music(){music = new ArrayList<String>();}
public int size(){return music.size();}
public void addSong(String song){music.add(song);}
public String getSong(){return music.get(music.size());}
public String getSong(int num){return music.get(num);}
public void removeSong(String song){
for(int i = 0; i < music.size(); i++){
if(music.get(i).equals(song)) {music.remove(i); return;}
}
}
public String toString(){
String s = "";
for(int i = 0; i < music.size(); i++){
s += music.get(i);
}
return s;
}
}
我的MusicDriver课程:
import java.util.*;
import java.io.*;
import javazoom.jl.player.Player;
import java.util.Random;
import java.util.Scanner;
import java.io.FileNotFoundException;
public class MusicDriver{
public static void main(String[] args) throws FileNotFoundException{
Random r = new Random();
Scanner s = new Scanner(System.in);
String line = "";
int number;
Music song = new Music();
song.addSong("1-01-overture.mp3");
song.addSong("1-03-fortune-teller-2.mp3");
song.addSong("1-07-prayer.mp3");
song.addSong("1-08-island-atlas.mp3");
song.addSong("1-12-warren-report.mp3");
song.addSong("1-13-avilla-hanya.mp3");
song.addSong("1-20-war-situation.mp3");
song.addSong("2-10-fog-of-phantom.mp3");
song.addSong("2-12-religious-precepts.mp3");
song.addSong("2-14-box-of-sentiment.mp3");
song.addSong("3-02-light-everlasting.mp3");
song.addSong("3-09-viking-spirits.mp3");
song.addSong("3-12-unsealed.mp3");
song.addSong("3-16-notice-of-death-reprise-.mp3");
//14 songs
ArrayList<Integer> songNums = new ArrayList<Integer>();
MP3 mp3 = new MP3();
do{
if(songNums.size() == song.size()) songNums.clear();
number = r.nextInt(song.size());
boolean done = false;
int counter = 0;
while(!done){
for(int i = 0; i < songNums.size(); i++){
if(number == songNums.get(i).intValue()) {number = r.nextInt(song.size()); counter++;}
}
if(counter == 0) done = true;
else done = false;
}
songNums.add(number);
mp3.playMP3(song.getSong(number));
System.out.println("Now Playing " + song.getSong(number));
System.out.println("Enter \"Stop\" to stop playing the song");
System.out.println("Enter \"n\" to play the next song");
line = s.nextLine();
mp3.stopMP3();
}while(line.equals("n"));
mp3.stopMP3();
}
}
我已经做了很多研究,为什么我的程序停止播放我的歌曲,但我找不到任何东西。我做了,发现BlueJ程序没有打开终端窗口(当你执行“System.out.print()”时出现的东西)如果你在输出之前要求输入但我不认为这个计划考虑到了这一点。我还确保当我想播放下一首歌时我输入了一个字符串“n”,对于前几首歌曲,它确实有效,但是在第八首歌之后,它就停止了。我很困惑。
答案 0 :(得分:7)
我认为唯一的问题在于你用来改组名单的逻辑。
number = r.nextInt(song.size());
boolean done = false;
int counter = 0;
while(!done){
for(int i = 0; i < songNums.size(); i++){
if(number == songNums.get(i).intValue()) {number = r.nextInt(song.size()); counter++;}
}
if(counter == 0) done = true;
else done = false;
}
当生成的随机数已存在于songNums列表中时,您将生成一个新的随机数。不会使用所有数量的songNums列表检查此新随机数。以下更改应解决您的问题。
boolean done = false;
while(!done){
number = r.nextInt(song.size());
if(!songNum.contains(number)) done = true;
}
或者,您可以在评论中使用Sasha的建议来改组列表(Collections.shuffle())。
答案 1 :(得分:3)
现有算法的实际问题是,当您发现已播放的歌曲时,您不会重置counter
。所以一旦你重复一次,就会陷入无限循环 - done
永远不会成真。
(实际上,它不会是无限的 - 一旦counter
到达Integer.MAX_VALUE
,它将回绕到Integer.MIN_VALUE
并最终再次到达0
,所以如果你离开它足够长,它最终会播放另一首歌)
这里已经提供了一些有关代码改进的有用建议,我在此不再赘述,但是修改所需内容的最小更改是将counter
的初始化移至{{1}在循环中:
0
答案 2 :(得分:3)
Sasha在评论中说:使用Collections.shuffle()。在实践中,这将是一个小小的&#39;像这样的东西:
在Music类中有一个获取所有歌曲的方法:
public List<String> getSongs() {return music;}
MusicDriver中的循环将遵循:
List<String> songs = song.getSongs();
do{
Collections.shuffle(songs);
for (String songToPly: songs) {
mp3.playMP3(song.getSong(number));
System.out.println("Now Playing " + song.getSong(number));
System.out.println("Enter \"Stop\" to stop playing the song");
System.out.println("Enter \"n\" to play the next song");
mp3.stopMP3();
line = s.nextLine();
if (!line.equals("n")) break;
}
}while(line.equals("n"));
在变量命名注释上,将您的音乐类的实例命名为&#34; song&#34; (单数)有点令人困惑。也许叫它&#34;音乐&#34;或者至少&#34;歌曲&#34;。
答案 3 :(得分:0)
我要做的是:
public class MainClass() {
public static void main(String[] args) {
PlayerWrapper player = new PlayerWrapper();
}
}
public class PlayerWrapper() {
private List<MP3> playlist;
private Scanner userInputReader;
private String currentUserInput;
public PlayerWrapper() {
userInputReader = new Scanner(System.in());
System.out.println("Filepath to playlist?");
String playlistFileName = userInputReader.nextLine();
playlist = PlayListExtractor.extractPlaylist(playlistFileName);
start();
}
public void start() {
playlistCopy = new ArrayList<MP3>(playlist);
shufflePlayList(playlistCopy);
Iterator<MP3> songIterator = playlistCopy.iterator();
while (songIterator.hasNext()) {
MP3 song = songIterator.next();
songIterator.remove();
player = new Player(song.toStream());
player.play();
displayCurrentSongAndCommands(song);
currentUserInput = userInputReader.nextLine();
if ("Stop".equals(currentUserInput )) {
player.close();
break;
} else if ("n".equals(currentUserInput )) {
player.close();
continue;
}
}
if("Stop".equals(currentUserInput)) {
System.out.println("Playlist stopped. Press q to quit or c to continue");
currentUserInput = userInputReader.nextLine();
if ("q".equals(currentUserInput)) {
System.exit(0);
} else if ("c".equals(currentUserInput)) {
start();
}
}
start();
}
private void shufflePlayList(final List<MP3> playlistToBeShuffled) {
long seed = System.nanoTime();
Collections.shuffle(playlistToBeShuffled, new Random(seed));
}
private void displayCurrentSongAndCommands(final MP3 currentSong) {
System.out.println("Now Playing " + currentSong.toString());
System.out.println("Enter \"Stop\" to stop playing the song");
System.out.println("Enter \"n\" to play the next song");
}
}
public static class PlayListExtractor() {
private PlayListExtractor();
public static List<MP3> extractPlayList(final String playListFileName) {
List<MP3> result = new ArrayList<>();
try (BufferedReader br = new BufferedReader(new FileReader(file))) {
String line;
while ((line = br.readLine()) != null) {
result.add(new MP3(line));
}
return result;
} catch (IOException e) {
System.out.println("Problem parsing playlist");
}
}
}
public class MP3 {
private String filename;
public MP3(final String filename) {
this.filename = filename;
}
public BufferedInputStream toStream() {
try {
FileInputStream fis = new FileInputStream(filename);
return new BufferedInputStream(fis);
}
catch (Exception e) {
System.out.println("Problem playing file " + filename);
System.out.println(e);
}
}
public String toString() {
return filename;
}
}