Question

我正在尝试创建一个代码，用于检查用户是否已完成测验，以及他们是否会将他们的分数放在他们之前的分数旁边，如果他们还没有添加他们的名字和分数。这是代码：

while count:

这是文本文件：

if userclass=="1":
   with open("Class1scores.txt","a+",) as class1file:
        lines = class1file.readlines() # all lines are stored here
        for i,line in enumerate(lines):
            if username in lines:
               print("yes")
               lines[i] = lines[i].strip() + ":" + str(score) + "\n"
            else:
                print("nope")
                with open("Class1scores.txt","w",) as class1file:
                     class1file.write(str(username) + ":" + str(score))
                     class1file.write("\n")
        class1file.seek(0)
        for line in lines:
            class1file.write(line)

class1file.close()

我希望它像：

Humzah:10
Humzah:0
Jack:10

它甚至不打印Yes nope所以我知道它与if语句有关但却不知道是什么？在这里输入代码

Answer 1

您的文件处理有点混乱。主要问题是您在写入模式下反复为不包含所需username的行重新打开文件，用您编写的新内容破坏其当前内容。当文件已经在附加模式下打开时，你就是这样做的，这更令人困惑。：）

我建议采用一种更简单的方法：将文件读入行列表，修改列表，然后编写修改后的列表。

请注意，您应该不 .close()在with声明中打开的文件：with会自动关闭该文件阻止退出。

from __future__ import print_function

fname = "Class1scores.txt"

#username, score = "Humzah", 0
#username, score = "Jack", 10
username, score = "Humzah", 10


# Read current file data into a list of lines, 
# discarding the newline at the end of each line
try:
    with open(fname, "r") as f:
        lines = f.read().splitlines()
except IOError:
    #Create empty list if no file exists.
    #This isn't totally robust, since other IO errors may occur.
    lines = []

#Scan each line to see if contains the current `username`
for i, line in enumerate(lines):
    if line.startswith(username):
        print(username, "found on line", i)
        lines[i] += ":" + str(score)
        break
else:
    #Control only gets here if we don't `break` out of the `for` loop
    print(username, "not found; appending to list")
    lines.append(username + ":" + str(score))

#Save modified list
data = "\n".join(lines) + "\n"
with open(fname, "w") as f:
    f.write(data)

这个Python代码有什么问题？为什么不编辑文本文件？

1 个答案: