我列出了以下数据。
我想按DocumentID对数据进行分组,然后想要使用逗号分隔符将DocPropIdentifyName和meta值组合在一起。输出如下:
我是通过使用下面的foreach来实现的:
var test = (from r in lstDocSearch
group r by r.DocumentID
into g
select new
{
DocumentID = g.Key,
MetaValues = g.ToList()
}).ToList();
List<DocSearch> list = new List<DocSearch>();
foreach (var item in test)
{
foreach (var item2 in item.MetaValues)
{
var check = list.Exists(x => x.DocumentID == item2.DocumentID);
if (check)
{
var find = list.FirstOrDefault(x => x.DocumentID == item2.DocumentID);
find.MetaValue = find.MetaValue + ", " + item2.MetaValue;
find.DocPropIdentifyName = find.DocPropIdentifyName + ", " + item2.DocPropIdentifyName;
}
else
{
DocSearch objDocSearch = new DocSearch();
objDocSearch.DocumentID = item2.DocumentID;
objDocSearch.DocPropIdentifyID = item2.DocPropIdentifyID;
objDocSearch.DocPropIdentifyName = item2.DocPropIdentifyName;
objDocSearch.MetaValue = item2.MetaValue;
list.Add(objDocSearch);
}
}
}
但我想用linq做这个,而不是循环遍历集合。可能吗?
答案 0 :(得分:2)
var test = (from r in lstDocSearch
group r by r.DocumentID
into g
select new
{
DocumentID = g.Key,
MetaValues = String.Join(",", g.Select(o => o.MetaValue)),
DocPropIdentifyNames = String.Join(",", g.Select(o => o.DocPropIdentifyName)),
}).ToList();