我正在开发一个将Firebase
用作BaaS
的应用。
问题是,即使在给出正确的firebase引用之后,我也会得到com.firebase.client.FirebaseException: Failed to bounce to type at com.firebase.client.DataSnapshot.getValue(DataSnapshot.java:183) at com.abc.xyz.MainActivity$2.onDataChange(MainActivity.java:119)
。堆栈跟踪中另一个值得注意的行是Caused by: com.fasterxml.jackson.databind.JsonMappingException: Conflicting setter definitions for property "colorFilter": android.widget.ImageView#setColorFilter(1 params) vs android.widget.ImageView#setColorFilter(1 params)
。
以下是Firebase
参考:Firebase mFirebaseRef = new Firebase("https://appname.firebaseio.com/users");
这是我的代码:
mFirebaseRef.addValueEventListener(new ValueEventListener() {
@Override
public void onDataChange(DataSnapshot snapshot) {
System.out.println("There are " + snapshot.getChildrenCount() + " blog posts");
for (DataSnapshot postSnapshot : snapshot.getChildren()) {
//error on this line
UsersDataFromFirebase post = postSnapshot.getValue(UsersDataFromFirebase.class);
View nameView = navigationView.getHeaderView(0);
userName = (TextView) nameView.findViewById(R.id.userName);
userName.setText(post.getUserName());
System.out.println(post.getUserName());
System.out.println(post.getUserEmail());
// View emailView = navigationView.getHeaderView(0);
// userEmail = (TextView) emailView.findViewById(R.id.userEmail);
// userEmail.setText();
userImageUrl = (URL) authData.getProviderData().get("profileImageUrl");
String userImageUrlString = userImageUrl.toString();
URL url = null;
try {
url = new URL(userImageUrlString);
} catch (MalformedURLException e) {
e.printStackTrace();
}
try {
image = BitmapFactory.decodeStream(url.openConnection().getInputStream());
} catch (IOException e) {
e.printStackTrace();
}
View imageView = navigationView.getHeaderView(0);
userImage = (ImageView) imageView.findViewById(R.id.userImage);
userImage.setImageBitmap(image);
}
}
@Override
public void onCancelled(FirebaseError firebaseError) {
System.out.println("The read failed: " + firebaseError.getMessage());
Toast.makeText(getBaseContext(), firebaseError.getMessage(), Toast.LENGTH_LONG).show();
}
});
} else {
android.app.AlertDialog.Builder builder = new android.app.AlertDialog.Builder(MainActivity.this);
builder.setTitle("No internet connection!");
builder.setMessage("Please connect to the internet.");
builder.setPositiveButton("Open Settings", new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialogInterface, int i) {
Intent intent = new Intent(Settings.ACTION_SETTINGS);
startActivity(intent);
//progressBar.setVisibility(View.INVISIBLE);
}
});
builder.setNegativeButton("Cancel", new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialogInterface, int i) {
//progressBar.setVisibility(View.INVISIBLE);
}
});
builder.show();
}
这是UsersDataFromFirebase.java
文件的代码:
public class UsersDataFromFirebase {
private String userName;
private String userEmail;
private ImageView userImage;
public UsersDataFromFirebase() {
// empty default constructor, necessary for Firebase to be able to deserialize blog posts
}
public String getUserName() {
return userName;
}
public String getUserEmail() {
return userEmail;
}
public ImageView getUserImage() {
return userImage;
}
}
由于Firebase
对我来说是一个非常新的东西,我无法弄清楚这里出了什么问题。
请告诉我。
提前致谢!
答案 0 :(得分:0)
您在Java类中包含了一个ImageView,Jackson / Firebase不知道如何将数据序列化。
解决方案是告诉Firebase / Jackson在从JSON读取/写入对象时忽略ImageView。
public class UsersDataFromFirebase {
private String userName;
private String userEmail;
private ImageView userImage;
public UsersDataFromFirebase() {
// empty default constructor, necessary for Firebase to be able to deserialize blog posts
}
public String getUserName() { return userName; }
public String getUserEmail() { return userEmail; }
@JsonIgnore
public ImageView getUserImage() { return userImage; }
}
请注意,这个问题在我对这个问题的回答中有所涉及:Why do I get "Failed to bounce to type" when I turn JSON from Firebase into Java objects?