Question

我有一个数据集，其中一列的标题是“您的位置和时区是什么？”

这意味着我们有像

这样的条目

丹麦，CET
位置是英格兰德文郡，格林威治标准时间
澳大利亚。澳大利亚东部标准时间+ 10h UTC。

甚至

一年中的大部分时间或在首尔，我的位置是俄勒冈州的尤金，韩国取决于学校假期。我的主要时区是太平洋时区。
整个五月我将在英国伦敦（GMT + 1）。在整个六月，我将在挪威（格林尼治标准时间+2）或以色列（GMT + 3），互联网接入有限。整个七月和八月我将在英国伦敦（GMT + 1）。然后从 2015年9月，我将在美国波士顿（EDT）

有没有办法从中提取城市，国家和时区？

我正在考虑创建一个包含所有国家/地区名称（包括简短形式）的数组（来自开源数据集）以及城市名称/时区，然后如果数据集中的任何单词与城市/国家/时区或短格式将其填充到同一数据集中的新列中并对其进行计数。

这是否实用？

===========基于NLTK答案的REPLT ============

运行与Alecxe相同的代码

Traceback (most recent call last):
  File "E:\SBTF\ntlk_test.py", line 19, in <module>
    tagged_sentences = [nltk.pos_tag(sentence) for sentence in tokenized_sentences]
  File "C:\Python27\ArcGIS10.4\lib\site-packages\nltk\tag\__init__.py", line 110, in pos_tag
    tagger = PerceptronTagger()
  File "C:\Python27\ArcGIS10.4\lib\site-packages\nltk\tag\perceptron.py", line 141, in __init__
    self.load(AP_MODEL_LOC)
  File "C:\Python27\ArcGIS10.4\lib\site-packages\nltk\tag\perceptron.py", line 209, in load
    self.model.weights, self.tagdict, self.classes = load(loc)
  File "C:\Python27\ArcGIS10.4\lib\site-packages\nltk\data.py", line 801, in load
    opened_resource = _open(resource_url)
  File "C:\Python27\ArcGIS10.4\lib\site-packages\nltk\data.py", line 924, in _open
    return urlopen(resource_url)
  File "C:\Python27\ArcGIS10.4\lib\urllib2.py", line 154, in urlopen
    return opener.open(url, data, timeout)
  File "C:\Python27\ArcGIS10.4\lib\urllib2.py", line 431, in open
    response = self._open(req, data)
  File "C:\Python27\ArcGIS10.4\lib\urllib2.py", line 454, in _open
    'unknown_open', req)
  File "C:\Python27\ArcGIS10.4\lib\urllib2.py", line 409, in _call_chain
    result = func(*args)
  File "C:\Python27\ArcGIS10.4\lib\urllib2.py", line 1265, in unknown_open
    raise URLError('unknown url type: %s' % type)
URLError: <urlopen error unknown url type: c>

Answer 1

我会使用自然语言处理和nltk提供的实体。

示例（严重基于this gist），它从文件中标记每一行，将其拆分为块并递归查找每个块的NE（命名实体）标签。更多解释here：

import nltk

def extract_entity_names(t):
    entity_names = []

    if hasattr(t, 'label') and t.label:
        if t.label() == 'NE':
            entity_names.append(' '.join([child[0] for child in t]))
        else:
            for child in t:
                entity_names.extend(extract_entity_names(child))

    return entity_names

with open('sample.txt', 'r') as f:
    for line in f:
        sentences = nltk.sent_tokenize(line)
        tokenized_sentences = [nltk.word_tokenize(sentence) for sentence in sentences]
        tagged_sentences = [nltk.pos_tag(sentence) for sentence in tokenized_sentences]
        chunked_sentences = nltk.ne_chunk_sents(tagged_sentences, binary=True)

        entities = []
        for tree in chunked_sentences:
            entities.extend(extract_entity_names(tree))

        print(entities)

对于sample.txt包含：

Denmark, CET
Location is Devon, England, GMT time zone
Australia. Australian Eastern Standard Time. +10h UTC.
My location is Eugene, Oregon for most of the year or in Seoul, South Korea depending on school holidays. My primary time zone is the Pacific time zone.
For the entire May I will be in London, United Kingdom (GMT+1). For the entire June I will be in either Norway (GMT+2) or Israel (GMT+3) with limited internet access. For the entire July and August I will be in London, United Kingdom (GMT+1). And then from September, 2015, I will be in Boston, United States (EDT)

打印：

['Denmark', 'CET']
['Location', 'Devon', 'England', 'GMT']
['Australia', 'Australian Eastern Standard Time']
['Eugene', 'Oregon', 'Seoul', 'South Korea', 'Pacific']
['London', 'United Kingdom', 'Norway', 'Israel', 'London', 'United Kingdom', 'Boston', 'United States', 'EDT']

输出并不理想，但对你来说可能是一个好的开始。

使用python从文本中提取城市名称

1 个答案: