Question

我想将我的用户发送到服务器并获取一个长号作为响应，但我在客户端遇到400错误并在服务器端获得此异常：

nested exception is com.fasterxml.jackson.databind.JsonMappingException: Can not deserialize instance of mashfood.model.User out of START_ARRAY token

我的客户端sUser模型与服务器用户模型完全相同：

sUser（或用户）：

class User{
public long id;

public String username;

public String password;

public String firstName;

public String lastName;

public String gender;

public String nationalNumber;

public String phoneNumber;

public String address;

public String email;

public boolean isLoggedIn;

public String imageUrl;

public int areaNumber;

}

客户端连接到服务器，如下所示： ** tClass是类型的响应 ** params [0]是我想发送给服务器的用户 ** url + conditions是处理获取用户的方法的url

protected ResponseHandler doInBackground(Object... params) {
    try {
        serverResponse=new ServerResponse();
        result = restTemplate.postForObject(URL + conditions, params,tClass);
        serverResponse.singleResult=result;
        serverResponse.isReady=true;
        responseHandler.onServerRespond(serverResponse);
    }catch (Exception e){
        serverResponse.isReady=false;
        serverResponse.message=e.getMessage();
        e.printStackTrace();
    }

    return responseHandler;
}

和服务器端代码是：

@RequestMapping(value = "/register",method = RequestMethod.POST)
@ResponseBody
public Long registerNewUser(@RequestBody User user){
    if(user!=null){
        try {
            System.out.println("REGISTER "+ user==null);
            SessionFactory sessionFactory=HibenateConnection.connectingHibernate();
            Session session=sessionFactory.openSession();
            session.beginTransaction();
            session.save(user);
            session.getTransaction().commit();
            User user1=getUser(user.username);
            session.close();
            return user1.id;
        }catch (Exception e){
            e.printStackTrace();
        }
    }
    return -1l;
}

我的输出JSON是：

[{
"address": "",
"areaNumber": 0,
"email": "email",
"firstName": "name",
"gender": "male",
"id": -1,
"imageUrl": "img",
"isLoggedIn": false,
"lastName": "lastn",
"nationalNumber": "898898",
"password": "pass",
"phoneNumber": "936",
"username": "mehdi"
}]

我的问题在哪里？

Answer 1

我的客户端JSON输出是以包含一个用户的用户列表的形式，并且我改变这样的服务器注册方法来解决我的问题：

@RequestMapping(value = "/register",method = RequestMethod.POST)
@ResponseBody
public boolean registerNewUser(@RequestBody List<User> users){
    if(users!=null){
        try {
            SessionFactory sessionFactory=HibenateConnection.connectingHibernate();
            Session session=sessionFactory.openSession();
            session.beginTransaction();
            session.save(users.get(0));
            session.getTransaction().commit();
            session.close();
            return true;
        }catch (Exception e){
            e.printStackTrace();
            return false;
        }
    }
    return false;
}

无法从START_ARRAY标记中反序列化对象的实例

1 个答案: