我目前有两个列表:
lat = [34.78, 34.82, 34.86, 34.92]
lon = [-86.02, -86.06, -86.10, -86.14]
我正在尝试编写一个csv文件,将它们输出为lat / lon:
34.78, -86.02
34.82, -86.06
34.86, -86.10
34.92, -86.14
我尝试使用:
with open('lat_lon', 'w') as csvfile:
writer=csv.writer(csvfile, delimiter=',')
writer.writerow(lat)
writer.writerow(lon)
但是这给了我一行中的lat值和一个单独行中的lon值。有关如何纠正此问题的任何想法?谢谢!
答案 0 :(得分:3)
您只需要zip并使用 writerows 而不是writerow:
with open('lat_lon', 'w') as csvfile:
writer=csv.writer(csvfile, delimiter=',')
writer.writerows(zip(lat, lon))
答案 1 :(得分:2)
你几乎就在那里,做到这一点:
with open('lat_lon', 'w') as csvfile:
writer = csv.writer(csvfile, delimiter=',')
for la, lo in zip(lat, lon):
writer.writerow([la, lo])
或者更简洁(如上所述):
with open('lat_lon', 'w') as csvfile:
writer = csv.writer(csvfile, delimiter=',')
writer.writerows(zip(lat, lon))
答案 2 :(得分:1)
import pandas as pd
lat = [34.78, 34.82, 34.86, 34.92]
lon = [-86.02, -86.06, -86.10, -86.14]
output = pd.DataFrame(lat, columns=['lat'])
output['lon'] = lon
output.to_csv('lat_lon', index=False)
答案 3 :(得分:0)
关键点是zip(lat,lon)。您可以使上述答案更加紧凑。
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