全部, 这可能在蜂巢中,如果是这样,这是最优化的方式吗?谢谢!
UPDATE t1
SET
Y = SQRT(Y_w)*(Y-(SELECT v FROM t2 WHERE ID=1)),
X1 = SQRT(Y_w)*(X1-(SELECT v1 FROM t2 WHERE ID=1)),
X2 = SQRT(Y_w)*(X2-(SELECT v2 FROM t2 WHERE ID=1)),
X3 = SQRT(Y_w)*(X3-(SELECT v3 FROM t2 WHERE ID=1)),
X4 = SQRT(Y_w)*(X4-(SELECT v4 FROM t2 WHERE ID=1)),
X5 = SQRT(Y_w)*(X5-(SELECT v5 FROM t2 WHERE ID=1)),
X6 = SQRT(Y_w)*(X6-(SELECT v6 FROM t2 WHERE ID=1)),
X7 = SQRT(Y_w)*(X7-(SELECT v7 FROM t2 WHERE ID=1)),
X8 = SQRT(Y_w)*(X8-(SELECT v8 FROM t2 WHERE ID=1));
答案 0 :(得分:0)
请验证您的查询。 它只有在t1有w列且t2有id列时才有效。