在functions.php中
awk -F= '$2 ~ /<br>/ { print $1 }' MyProject.properties
如何获取假设url具有所有参数的参数?在我的主题php文件中。我用
function add_query_vars_uniqlo($aVars) {
$aVars[] = array("qtext",
"qbrand",
"qnew",
"qdiscount",
"qlimit",
"qmulti",
"qonline",
"qspsize",
"qrange",
"qcolor",
"qsize",
"qicon",
"qstart",
"sort",
"qclv1",
"uniqlo_url");
return $aVars;
}
// hook add_query_vars function into query_vars
add_filter('query_vars', 'add_query_vars_uniqlo');
global $wp_query;
$aVars[] = array("qtext",
"qbrand",
"qnew",
"qdiscount",
"qlimit",
"qmulti",
"qonline",
"qspsize",
"qrange",
"qcolor",
"qsize",
"qicon",
"qstart",
"sort",
"qclv1",
"uniqlo_url");
if(isset($wp_query->query_vars($aVars))) { //Do some thing}
是否正确?