Question

我想创建一个动画，显示潜水员跳入水中。

通过水的潜水员原始高度的给定参数h和他的质量m，我在Python中定义了一个程序来计算他接触水的时刻，{{1} }。

知道他垂直跳跃，X轴是固定的，并且 Y轴服从方程（1/2） g t ^ 2 + h（g是引力常数）

如果时间Tc在范围内（t），我如何绘制图表，X轴和Y轴显示潜水员的投影？（Tc已修复且x取决于时间y）

在图形窗口中，我们应该会看到一个“跳跃”的点。从某个高度垂直向下，没有看到投影线/迹线。

这是我工作的一部分。我不知道在程序中引入t的位置：

Tc

编辑：

这是整个计划。我应用并修改了@Mike Muller给出的建议，但它没有起作用。我不明白哪里出错了。希望你能澄清我的怀疑。

import numpy as np
from matplotlib import pyplot as plt
from matplotlib import animation

# First set up the figure, the axis, and the plot element we want to animate
fig = plt.figure()
ax = plt.axes(xlim=(0, 2), ylim=(-2, 2))
line, = ax.plot([], [], lw=2)

# initialization function: plot the background of each frame
def init():
    line.set_data([], [])
    return line,

# animation function.  This is called sequentially
def animate(i):
    x = np.empty(n) ; x.fill(1)   # the vertical position is fixed on x-axis
    y = 0.5*g*i^2 + h             # the equation of diver's displacement on y axis

    line.set_data(x, y) 
    return line,

# call the animator.  blit=True means only re-draw the parts that have changed.
anim = animation.FuncAnimation(fig, animate, init_func=init,
        frames=200, interval=20, blit=True)

plt.show()

Answer 1

基于原始问题的答案

您需要使用生成器来生成y数据。这有效：

import numpy as np
from matplotlib import pyplot as plt
from matplotlib import animation

# First set up the figure, the axis, and the plot element we want to animate
fig = plt.figure()
ax = plt.axes(xlim=(0, 2), ylim=(-2, 2))
line, = ax.plot([], [], ' o', lw=2)
g = 9.81
h = 2
tc = 200
xs = [1] # the vertical position is fixed on x-axis
ys = [h, h]


# animation function.  This is called sequentially
def animate(y):
    ys[-1] = y
    line.set_data(xs, ys)
    return line,

def get_y():
  for step in range(tc):
    t = step / 100.0
    y = -0.5*g*t**2 + h  # the equation of diver's displacement on y axis
    yield y

# call the animator.  blit=True means only re-draw the parts that have changed.
anim = animation.FuncAnimation(fig, animate, frames=get_y, interval=100)

plt.show()

综合答案

这应该有效：

# -*- coding: utf-8 -*-

from math import *
import numpy as np
from matplotlib import pyplot as plt
from matplotlib import animation


def Plongeon():
    h = float(input("height = "))
    g = 9.81

    #calculate air time, Tc
    Tc = sqrt(2 * h / g)

    # First set up the figure, the axis, and the plot element we want to animate
    fig = plt.figure()
    ax = plt.axes(xlim=(0, 2), ylim=(-2, h+1))  #ymax : initial height+1
    line, = ax.plot([], [], ' o', lw=2)

    step = 0.01  # animation step
    xs = [1]  # the vertical position is fixed on x-axis
    ys = [h]


    # animation function.  This is called sequentially
    def animate(y):
        ys[-1] = y
        line.set_data(xs, ys)
        return line,

    def get_y():
        t = 0
        while t <= Tc:
            y = -0.5 * g * t**2 + h  # the equation of diver's displacement on y axis
            yield y
            t += step

    # call the animator.  blit=True means only re-draw the parts that have changed.
    anim = animation.FuncAnimation(fig, animate, frames=get_y, interval=100)

    plt.show()
Plongeon()

我删除了不需要的行。无需global。此外，程序中的任何地方都没有使用质量。

这是最重要的部分：

def get_y():
     t = 0
     while t <= Tc:
         y = -0.5 * g * t**2 + h 
         yield y
         t += step

你需要增加一点时间。

如何绘制实时图形，两个轴都依赖于时间？

1 个答案:

基于原始问题的答案

综合答案