我正在努力解决以下python问题。我想从现有列表创建一个json输出，但它是一个我无法实现的3级结构。
我知道如何创建一个2级结构：
data = json.dumps(
[ {'book_id': i, 'exam': [{'count': k, 'wordids': w}]} \
for k,i,w, in \
zip(examcounts, bookid_list, wordid_list)],
indent=4)
它产生一个有效的2级结构，但我需要以某种方式实现另一个for循环，我只是无法弄清楚如何。
所以希望的输出应该是这样的：
[
{
"book_id": "a",
"exams": [
{
"exam": [
{
"result":"B"
"wordids": [
25201L,
41851L,
10134L
]
}
],
"exam": [
{
"result":"A"
"wordids": [
43,
41,
10
]
}
]
}
]
},
{
"book_id": "b",
"exams": [
{
"exam": [
{
"result":"C"
"wordids": [
25,
10
]
}
],
"exam": [
{
"result":"C"
"wordids": [
25,
10
]
}
],
"exam": [
{
"result":"F"
"wordids": [
43,
41,
]
}
]
}
]
}
]
列出示例：
bookid_list: [u'a', u'b']
exmcounts: [22, 22, 20, 21, 21, 21, 21, 18]
results: ['B','A','C','C','F'...] with 8 length
wordid_list: [[25201L, 41851L, 10134L, 12174L, 6899L, 26078L, 12457L, 12176L, 26056L, 9451L, 25164L, 6618L, 43482L, 18681L, 12370L, 43272L, 15561L, 43483L, 30121L, 7715L, 21111L, 9461L], [13822L, 5172L, 7176L, 25754L, 12372L, 5509L, 16712L, 6187L, 8263L, 15408L, 20262L, 43487L, 5143L, 43488L, 6145L, 5697L, 7581L, 43489L, 22538L, 19417L, 43491L, 21498L], [19475L, 11631L, 12172L, 19495L, 30396L, 37274L, 43493L, 32393L, 5945L, 37521L, 6956L, 43494L, 36517L, 43495L, 13255L, 6558L, 12867L, 13382L, 6489L, 15447L]]
（wordid列表的长度为8，每个项目的长度为22,22,20,21 ..） 非常感谢提前！
答案 0 :(得分：0)
尝试将您的数据打成3级词典。
dic = {'book_id': 'a', 'exams': {'exam1' : {'result': 'b', 'wordids': [25, 41, 10] } } }
data = json.dumps(dic)
只要所有类型都是JSON可序列化的，你就应该从3级字典中获得3级JSON。
答案 1 :(得分：0)
假设所有列表长度相同，您可以将每个列表添加到zip()并将每个列表嵌入到json字符串中。下面的示例包含三个元素的列表，可以根据需要扩展到8：
import json
bookid_list = [u'a', u'b', u'c']
examcounts = [22, 22, 20]
results = ['B','A','C']
wordid_list = [[25201, 41851, 10134, 12174, 6899, 26078, 12457, 12176, 26056,
9451, 25164, 6618, 43482, 18681, 12370, 43272, 15561, 43483,
30121, 7715, 21111, 9461],
[13822, 5172, 7176, 25754, 12372, 5509, 16712, 6187, 8263,
15408, 20262, 43487, 5143, 43488, 6145, 5697, 7581, 43489,
22538, 19417, 43491, 21498],
[19475, 11631, 12172, 19495, 30396, 37274, 43493, 32393, 5945,
37521, 6956, 43494, 36517, 43495, 13255, 6558, 12867, 13382, 6489, 15447]]
data = json.dumps(
[ {'book_id': b, 'exams': [{'exam': [{'results': r, 'wordids': w}]}]} \
for b,e,r,w, in \
zip(bookid_list, examcounts, results, wordid_list)],
indent=4)
print(data)
<强>输出
[
{
"book_id": "a",
"exams": [
{
"exam": [
{
"results": "B",
"wordids": [
25201,
41851,
10134,
12174,
6899,
26078,
12457,
12176,
26056,
9451,
25164,
6618,
43482,
18681,
12370,
43272,
15561,
43483,
30121,
7715,
21111,
9461
]
}
]
}
]
},
{
"book_id": "b",
"exams": [
{
"exam": [
{
"results": "A",
"wordids": [
13822,
5172,
7176,
25754,
12372,
5509,
16712,
6187,
8263,
15408,
20262,
43487,
5143,
43488,
6145,
5697,
7581,
43489,
22538,
19417,
43491,
21498
]
}
]
}
]
},
{
"book_id": "c",
"exams": [
{
"exam": [
{
"results": "C",
"wordids": [
19475,
11631,
12172,
19495,
30396,
37274,
43493,
32393,
5945,
37521,
6956,
43494,
36517,
43495,
13255,
6558,
12867,
13382,
6489,
15447
]
}
]
}
]
}
]