为了解释下面的查询,您应该知道我在查询中使用了当前用户的三个变量...
$radius
用户希望在
$lat
用户的纬度
$lon
用户的经度
zipData表中的相关列是zipcode
lon
和lat
我有这个查询,可以报告所需半径范围内的所有其他用户......
$query="
SELECT username FROM zipData,seekers
WHERE (POW((69.1*(lon-\"$lon\")*cos($lat/57.3)),\"2\")+POW((69.1*(lat-\"$lat\")),\"2\"))<($radius*$radius)
AND replace(seekers.postal,' ','') = zipData.zipcode;
";
我也有此查询,只返回符合特定条件的特定用户...
$query="
SELECT *
FROM
(
SELECT a.username, MATCH(a.highlight) AGAINST (\"{$keywords}\" IN BOOLEAN MODE) AS score
FROM resume_highlights a
JOIN seekers ON a.username = seekers.username and seekers.resume_status = 1
HAVING score>0
UNION ALL
SELECT b.username, MATCH(b.skill,b.skill_list) AGAINST (\"{$keywords}\" IN BOOLEAN MODE) AS score
FROM resume_skills b
JOIN seekers ON b.username = seekers.username and seekers.resume_status = 1
HAVING score>0
UNION ALL
SELECT c.username, MATCH(c.education_title,c.education_organization) AGAINST (\"{$keywords}\" IN BOOLEAN MODE) AS score
FROM resume_education c
JOIN seekers ON c.username = seekers.username and seekers.resume_status = 1
HAVING score>0
UNION ALL
SELECT d.username, MATCH(d.employer_title,d.employer_organization) AGAINST (\"{$keywords}\" IN BOOLEAN MODE) AS score
FROM resume_employer d
JOIN seekers ON d.username = seekers.username and seekers.resume_status = 1
HAVING score>0
UNION ALL
SELECT e.username, MATCH(e.volunteer_title,e.volunteer_organization) AGAINST (\"{$keywords}\" IN BOOLEAN MODE) AS score
FROM resume_volunteer e
JOIN seekers ON e.username = seekers.username and seekers.resume_status = 1
HAVING score>0
) AS X
ORDER BY score desc
";
两个查询都独立工作;但是,我将它们组合成一个查询所做的每一次尝试都导致执行时间非常慢。
我在seekers.postal
zipData.lon
和zipData.lat
上有索引。我会认为这样做会有所作为,但事实并非如此。可能只是我构建了错误的查询,所以我想看看如何组合2个查询。
答案 0 :(得分:1)
我认为link有你的答案:
提高SELECT操作性能的最佳方法是 在一个或多个在中测试的列上创建索引 查询。索引条目就像指向表行的指针一样,允许 查询以快速确定哪些行匹配条件 WHERE子句,并检索这些行的其他列值。所有 MySQL数据类型可以编入索引。