如何将以下格式的字符串解析为关联数组?
[ ["key1", "value1"], ["key2", "value2"], ["key3", "value3] ]
进入:
Array
(
["key1"] => "value1"
["key2"] => "value2"
["key3"] => "value3"
)
谢谢!
编辑:数据采用字符串格式,即:
$stringdata ='[ ["key1", "value1"], ["key2", "value2"], ["key3", "value3"] ]';
答案 0 :(得分:1)
使用循环并循环遍历整个数组,并使用第一个元素作为键,将第二个元素作为值,将值分配到新数组中。通常是这样的:
$new_array = array();
foreach($array as $arr) {
$new_array[$arr[0]] = $arr[1];
}
但是要将字符串解析为数组,我将采用以下RegEx方法然后循环:
$str = '[ ["key1", "value1"], ["key2", "value2"], ["key3", "value3"] ]';
preg_match_all('/(\[("(.*?)"), ("(.*?)")\])/i', $str, $matches);
//Now we have in $matches[3] and $matches[5] the keys and the values
//and we would now turn this into an array using a loop
$new_array = array();
for($k = 0; $k < count($matches[3]); $k++) {
$new_array[$matches[3][$k]] = $matches[5][$k];
}
查看此实时演示https://3v4l.org/u3jpl
答案 1 :(得分:0)
FOUND
输出:
<?php
$ar = [ ["key1", "value1"], ["key2", "value2"], ["key3", "value3"] ];
$newAr = array_reduce($ar, function($carry, $item) {
$carry[$item[0]] = $item[1];
return $carry;
});
var_dump($newAr);
答案 2 :(得分:0)
以下是使用json_decode的解决方案。
<?php
$json = json_decode('[["key1", "value1"], ["key2", "value2"], ["key3", "value3"]]');
$final = array();
foreach($json as $value) {
$final[] = array($value[0]=>$value[1]);
}
final
是您所需格式的数组。