Question

我有新问题。我从客户端请求创建了一些生成谓词的代码。这是初始化部分：

 criteriaBuilder = entityManager.getCriteriaBuilder();
 criteriaQuery = criteriaBuilder.createQuery(classEntity);
 root = criteriaQuery.from(classEntity);

当我想要获取列表实体时，它工作得很好：

criteriaQuery.select(root).where(predicate);
entityManager.createQuery(criteriaQuery).getResultList();

但是当我想获得计数实体时：

CriteriaQuery<Long> cq = criteriaBuilder.createQuery(Long.class);
cq.select(criteriaBuilder.count(root)).where(predicate);
System.err.println("eee : " +entityManager.createQuery(cq).getSingleResult());

它有异常

java.lang.IllegalArgumentException: Error occurred validating the Criteria Caused by: java.lang.IllegalStateException: No criteria query roots were specified

可能我应该说，root生成动态连接：

private Path parseField(String field) {
    Path path = null;

    if (field.contains(".")) {

        String [] split = field.split("\\.");
        Join join = root.join(split[0],JoinType.INNER);

        for (int i =1; i < split.length-1; i++) {
            join = join.join(split[i],JoinType.INNER);
        }

        path = join.get(split[split.length-1]);

    } else {
        path = root.get(field);
    }
    return path;
}

如果我替换

cq.select(criteriaBuilder.count(root)).where(previousPredicate);

在

cq.select(criteriaBuilder.count(cq.from(classEntity))).where(previousPredicate);

我将失败，异常

 org.hibernate.hql.ast.QuerySyntaxException: Invalid path: 'generatedAlias1.(someFieldName)'

Answer 1

一切都适合我：

CriteriaBuilder cb = em.getCriteriaBuilder();
CriteriaQuery<Long> q = cb.createQuery(Long.class);
Root<A> r = q.from(A.class);
MapJoin<A, String, String> m = r.joinMap("metadata");
q.select(cb.count(r)).where(cb.equal(m.key(), "A"));
Long rs = em.createQuery(q).getSingleResult();

所以，如果没有MCVE，很难看出你做错了什么。

Jpa标准计数

1 个答案: